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sdas [7]
3 years ago
6

A hacker using information gathered from sniffing network traffic uses your banking credentials from a recent transaction to cre

ate nearly duplicate bank transfers but alters the target account to steal the funds. The attacker is reproducing traffic to re- create an event from previous transactions. This is an example of what type of attack?
A. Xmas attack
B. Smurf attack
C. DDoS attack
D. Replay attack
Computers and Technology
1 answer:
adell [148]3 years ago
3 0

Answer: a replay attack, a replay attack is used so that the attacker can go sniff out the hash, and get whatever they are trying to get, then once it goes to the attacker it will go back to the original connection after replaying the hash

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You are !o code and execute a C program to input narnes ard addresses t]rat are in alphabctic order and output the names and add
alexgriva [62]

Answer:

#define MAX 50

#include <stdlib.h>

#include <stdio.h>

#include <string.h>

struct address

{

char name[MAX];

char street[MAX];

char city[MAX];

char zip[10];

};

void in(struct address *, int *);

void sort(struct address *, int);

void out(struct address *, int);

int main(){

struct address *ADDRESS = (struct address *)malloc(50*sizeof(struct address));

int n=0;

in(ADDRESS, &n);

sort(ADDRESS, n);

out(ADDRESS, n);

}

void in(struct address *ADDRESS, int *num)

{

FILE *fp;

char fname[MAX];

printf("Enter input file name: ");

scanf("%s", fname);

fp = fopen(fname, "r");

if (fp == NULL)

{

printf("Unable to open file");

exit(1);

}

int a = 0;

while (!feof(fp))

{

//ADDRESS = (struct address *)realloc(ADDRESS, (a + 1) * sizeof(struct address));

if(a>=50)

break;

fscanf(fp, "\n%[^\n]s", (ADDRESS+a)->name);

fscanf(fp, "\n%[^\n]s", (ADDRESS+a)->street);

fscanf(fp, "\n%[^\n]s", (ADDRESS+a)->city);

fscanf(fp, "\n%[^\n]s", (ADDRESS+a)->zip);

a++;

}

printf("Successfully %d read from file\n", a);

*num = a;

}

void sort(struct address *ADDRESS, int num){

int i, j;

for(i=0; i<num; i++){

for(j=i+1; j<num;j++){

if(strcmp((ADDRESS+i)->zip, (ADDRESS+j)->zip)>0){

struct address t = *(ADDRESS+i);

*(ADDRESS+i) = *(ADDRESS+j);

*(ADDRESS+j) = t;

}

}

}

}

void out(struct address *ADDRESS, int num)

{

FILE *fp;

char fname[MAX];

printf("Enter output file name: ");

scanf("%s", fname);

fp = fopen(fname, "w");

if (fp == NULL)

{

printf("Unable to open file");

exit(1);

}

int a;

for(a=0; a<num; a++)

{

fprintf(fp, "%s\n", (ADDRESS+a)->name);

fprintf(fp, "%s\n", (ADDRESS+a)->street);

fprintf(fp, "%s\n", (ADDRESS+a)->city);

fprintf(fp, "%s\n", (ADDRESS+a)->zip);  

}

printf("Successfully %d Write to file\n", a);

fclose(fp);

}

Explanation:

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Answer:

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Explanation:

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tia_tia [17]
I believe the answer is B spread sheet because i use spread sheets to make my life easier. I organize info in a spread sheet then it is really easy to find.

hope this helps<span />
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