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Kaylis [27]
3 years ago
5

Y-3(2y-7)=76 i dont understand please help

Mathematics
2 answers:
Irina18 [472]3 years ago
6 0
Y=-11
that’s your answer :))
e-lub [12.9K]3 years ago
3 0

Answer:

y = -11

Step-by-step explanation:

y - 3 (2y - 7) = 76

distribute the three to the two values in the parenthesis!

y - 6y + 21 = 76

now combine like terms, baiscally add y to -6y

-5y + 21 = 76

now subtract 21 from both sides

-5y = 55

then divide by negative 5

y = -11

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Crank

Answer:

the daimeter of the heart of the heart of the heart

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The length of 9 ants measure 3.51 inches. What is the length of 25 ants measured in inches if each ant is 1 cementer long?
valentina_108 [34]

Answer:

if 9 ants=3.51inches

25 ants =x

therefore by cross multiplication

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3 years ago
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goldenfox [79]

Answer:

= 6 {t}^{4}   - 6 {t}^{3}  + 3t + 1

Step-by-step explanation:

6 {t}^{4}  - t + 1 - 6 {t}^{3}  + 4t \\  = 6 {t}^{4}   - 6 {t}^{3}  + 3t + 1

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3 years ago
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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