103^2-102^2
The property that applies here is a^2-b^2 = (a+b)(a-b)
so the answer is 103^2-102^2=(102+103)*(103-102)= numerically it is 205( as 103+102 = 205 and 103-102 = 1.....so 205*1 = 205)
The thing is that usually the factorization ends at (102+103)(102-103) ......
Answer:
x =
Step-by-step explanation:
First, add like terms. You can take out the x if it's too confusing and add it again.
-5/8 - 7/24 + 1/3 (multiply get a common denominator--in this case it's 24)
-15/24 - 7/24 + 8/24
-14/24 (then, simplify!)
-7/12
(add back the x → -7/12x)
-7/12x = -56 (multiply by reciprocal)
(-12/7) (-7/12x) = (-56) (-12/7)
x = 96
