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3 years ago

T = kPV solve for p. literal equations

Mathematics

2 answers:

storchak [24]3 years ago

6 0

Answer:

T/(kV) = P

Step-by-step explanation:

Step 1: Write equation

T = kPV

Step 2: Solve for <em>p</em>

Divide both sides by kV: T/(kV) = P

polet [3.4K]3 years ago

4 0

Answer:

P = T/(kV)

Step-by-step explanation:

Divide by the coefficient of P.

$T=kPV\\\\\dfrac{T}{kV}=\dfrac{kPV}{kV}\\\\\dfrac{T}{kV}=P\\\\\boxed{P=\dfrac{T}{kV}}$

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Complete this proof.

Alja [10]

Answer:

1) distributive property

2) subtraction property of equality

3) division property of equality

Step-by-step explanation:

Given : If $\frac{1}{2}(8x+14)=39$ , then x=8

To complete the proof :

Solution :

Following are the complete steps or proof of solving the given expression,

$\frac{1}{2}(8x+14)=39$ is given

$4x + 7 = 39$ - distributive property

$4x = 32$ - subtraction property of equality

$x = 8$ - division property of equality

3 0

3 years ago

Read 2 more answers

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago

In a true-false test containing 50 questions, a student is to be awarded 2 marks for every correct answer and -2 for every incor

BlackZzzverrR [31]

Answer:

1. 47 correct, 0 wrong and 3 unanswered

2. 48 correct, 1 wrong and 1 unanswered

Step-by-step explanation:

Given;

Total number of questions = 50

For correct answers = 2

For wrong answers = -2

Unanswered questions = 0

Yash scored 94 marks

Let c, w and u represent the number of correct, wrong and unanswered questions

2×c - 2 × w + 0×u = 94

2c -2w = 94 .....1

And;

c + w + u = 50 .....2

We have 2 equations and 3 unknowns

By observing the problem, we can see two possible solutions;

Case 1: Assuming he did not miss (get wrong) any answer;

He needs to score 47 answers right;

47 × 2 = 94

Then;

c = 47 w = 0 and u = 50 - (47+0) = 3

47 correct, 0 wrong and 3 unanswered

Case 2: Assuming he got one answer wrong;

He would need to score one more answer right compared to the first case;

(47+1) × 2 - 1 × 2 = 96 - 2 = 94

c = 47+1 = 48

w = 1

u = 50 - (48+1) = 1

So he need to score 48 correct answers, 1 wrong answer and 1 unanswered.

3 0

3 years ago

U are very annoying mr poophead

Sliva [168]

Answer:

Step-by-step explanation:

yes

6 0

3 years ago

Read 2 more answers

Variable p is 2 more than variable d. Variable p is also 1 less than variable d.

prohojiy [21]

Step-by-step explanation:

The correct answer is p= 2+d and p= d-1

3 0

3 years ago