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snow_lady [41]
4 years ago
6

Please explain the concept and give at least one real world example that demonstrates the concept that you have selected.

Mathematics
1 answer:
Naily [24]4 years ago
8 0
Well, think of triangles you see in real life! A dorito could work, for example, but any triangular object is fine. If it wants just a triangular angle and not a literal triangle, the letter v is a good example because the angle in the v could be a triangle if you added one more side? I hope this makes sense
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Please help me with this.
tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

<h3>r(- 3): </h3>

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

<h3>r(- 1):</h3>

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

<h3>r(1):</h3>

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

<h3>r(5):</h3>

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

7 0
2 years ago
Find the volume of the cube below.
rosijanka [135]
The answer is 125cm^3
5 0
4 years ago
Read 2 more answers
Given that the series kcoskt kº +2 k=1 converges, suppose that the 3rd partial sum of the series is used to estimate the sum of
3241004551 [841]

Answer:

c

Step-by-step explanation:

Given that:

\sum \limits ^{\infty}_{k=1} \dfrac{kcos (k\pi)}{k^3+2}

since cos (kπ) = -1^k

Then, the  series can be expressed as:

\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^kk)}{k^3+2}

In the sum of an alternating series, the best bound on the remainder for the approximation is related to its (n+1)^{th term.

∴

\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^{(3+1)}(3+1))}{(3+1)^3+2}

\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^{(4)}(4))}{(4)^3+2}

= \dfrac{4}{64+2}

=\dfrac{2}{33}

5 0
3 years ago
What is the simplified form of √10,000x^64?
kow [346]
<span>c. 100x^8 because the square root or 10k is 100 and 64 is 8

</span>
8 0
4 years ago
Read 2 more answers
Find the limit of the function algebraically lim (x^2 -36 / x+6 ) x -&gt;6
posledela

9514 1404 393

Answer:

  0

Step-by-step explanation:

The function is defined everywhere except at x=-6. The limit value is the function value at that point.

  f(6) = (6^2 -36)/(6 +6) = 0/12 = 0

The limit of the function is 0 as x → 6.

3 0
3 years ago
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