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nalin [4]
3 years ago
12

Which equations represents a line that passes through (4, 1/3) and has a slope of 3/4

Mathematics
2 answers:
suter [353]3 years ago
8 0

Answer:

y=3/4x-8/3

Step-by-step explanation:

y-y1=m(x-x1)

y-1/3=3/4(x-4)

y-1/3=3/4x-12/4

y-1/3=3/4x-3

y=3/4x-3+1/3

y=3/4x-9/3+1/3

y=3/4x-8/3

docker41 [41]3 years ago
6 0

Answer:

y = 3/4x - 8/3

Step-by-step explanation:

y = 3/4x + b

1/3 = 3/4(4) + b

1/3 = 3 + b

-8/3 = b

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3 years ago
Add 7 plus 8, then add a to the result. Write an expression for the sequence of operations described.
Ipatiy [6.2K]

Answer:

(7 + 8) + a is your answer

4 0
3 years ago
Given a line with equation 3x +7y = 21. write an equation in point-slope form of the line parallel to the given line through the
guapka [62]

Answer:

The equation of the line is y = -3/7x - 23/7

Step-by-step explanation:

To start we need to find the slope of the original line. We can do this by solving the equation for y.

3x + 7y = 21

7y = -3x + 21

y = -3/7x + 3

Now we know the slope to be -3/7. Since parallel lines have same slopes, we know the new line also will have a -3/7 slope. We can now use that along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 5 = -3/7(x - 4)

y + 5 = -3/7x + 12/7

y = -3/7x - 23/7

8 0
3 years ago
There are 363 students at Meadowbrook High School. There are 10 more
saveliy_v [14]
First, put each grade in terms of x. Most grades are compared to Sophomores, so I made that x

Freshmen = x + 10
Sophomores = x
Juniors = x + 20
Seniors = (x + 10) + 7 = x + 17

Then, the total number of students = 363, so we’ll make an equation that adds them all up in terms of x to equal 363

(x + 10) + x + (x + 20) + (x + 17) = 363

Combine like terms:
4x + 47 = 363
Subtract 47 from both sides:
4x = 316
Divide both sides by 4:
x = 79

The question was how many seniors there are. Seniors were x + 17, so 79 + 17 = 96
4 0
3 years ago
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