Answer:
5 to the power of 5
Step-by-step explanation:
Let the boy be B and the girl be G
there are six possible outcomes
BGG, GBB, GBG, BGB, BBB, and GGG
therefore the probability of getting one boy and two girls is
also the probability of getting 3 girls is
so when we add to the function outside of the parentheses of (x)^3, we are moving the graph in the up down direction so it would look like x^3 but shifted up 2 units. the way to easily know which one it is, plug in zero for x in the original and 0^3 is zero so we know the original fuction will go through the origin so the function who's center is is only shifted up (because it's positive 2) two units so graph 1
note: the reason i know that what looks like a center point is actually at the origin is because f(x)= x^3 is a very famous graph that you should know the shape of :)
Step-by-step explanation:
Multiply
0.15
by
−
0.6
.
−
0.09
Answer:
k = 1
P(t) = (t + 20)²
Step-by-step explanation:
P' = k√P = k P⁰•⁵
To solve for k,
P' = 10 rabbits/month
P = 100 rabbits
10 = k √100
10 = 10k
k = 1
To solve for P(t)
P' = dP/dt
(dP/dt) = kP⁰•⁵
dP/P⁰•⁵ = k dt
P⁻⁰•⁵ dP = k dt
∫ P⁻⁰•⁵ dP = ∫ k dt
2P⁰•⁵ = kt + c
At t = 0, P = 100
2(100)⁰•⁵ = 0 + c
2 × 10 = c
c = 20
2P⁰•⁵ = kt + c
2P⁰•⁵ = kt + 20
Recall, k = 1
2P⁰•⁵ = t + 20
P⁰•⁵ = (t + 20)
P(t) = (t + 20)²