Answer:
The normality requirement for a confidence interval estimate of sigma is (stricter) than the normality requirement for a confidence interval estimate of mu. Departures from normality have a (greater) effect on confidence interval estimates of sigma than on confidence interval estimates of mu. That is, a confidence interval estimate of sigma is (less)
Step-by-step explanation:
a. The mean can be found using the AVERAGE() function.
x = 272.7
b. The standard deviation can be found with the STDEV() function.
s = 39.9
c. The t-score can be found with the T.INV.2T() function. The confidence level is 0.04, and the degrees of freedom is 26.
t = 2.162
d. Find the lower and upper ends of the confidence interval.
Lower = 272.7 − 2.162 × 39.9 = 186.5
Upper = 272.7 + 2.162 × 39.9 = 358.9
Answer: B' (5,8), C' (3,1)
Step-by-step explanation:
You can use the points A' (-1,8) and A (-2,-3) to find how many units point A was translated.
-2 + 1 = -1
-3 + 11 = 8
Then, you simply add 1 to the x-values of points B and C and 11 to the y-values of points B and C to get B' (5,8), C' (3,1).
I hope this helps!
F(x)=-5t^2+20t+60
Divide everything by -5
f(x)=t^2-4t-12
(t-6)(t+2)
Set it up to zero
t-6=0. t+2=0
t=6. t=-2
Since you can’t have negative seconds, the answer is 6 seconds
