How do i make 5x+2y=4 into the form of y=mx+b

1 answer:

6 0

First you minus 2y on both sides and you get: 5x=-2y+4. Then you minus 4 on both sides to get 5x-4=-2y which in turn is y (-2y) = mx (5x) + b (-4) : -2y=5x-4

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I NEED HELP FAST!!!!!!!!!!

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How do you solve this problem

Kryger [21]

Answer:

$sin(A) = \frac{21}{{29} }$

$cos(A)=\frac{20}{29 }$

$tan(A)=\frac{21}{20}$

$sin(C) = \frac{20}{{29} }$

$cos(C)=\frac{21}{29 }$

$tan(C)=\frac{20}{21}$

Step-by-step explanation:

So first we need to make sure we know the trig identities to solve this problem.

$sin(\alpha )=\frac{opposite}{hypotenuse}$
$cos(\alpha )=\frac{adjacent}{hypotenuse}$
$tan(\alpha )=\frac{opposite}{adjacent}$

Here we only have two legs of the triangle, so we will need to use the Pythagorean Theorem a² + b² = c² to solve for the missing leg, the hypotenuse in this case.

Solving for the hypotenuse, c, we get $c = \sqrt{a^{2} +b^{2} }$
Here a = 20 and b = 21, so plugging in these values to the equation we get: $c= \sqrt{(20)^{2}+(21)^{2} } =\sqrt{400+441} =\sqrt{841}=29$