Based in your question that ask to evaluate the integral of tan^2(x)sec(x), base on my calculation and the use of the integral procedures and formula i came up with a solution that could answer your question and the evaluated answer is <span>tan(x)sec(x)−∫(<span>sec2</span>(x)−1)sec(x)dx</span>
Answer:
34 for the first box but ?? the last one
Step-by-step explanation:
Answer:
21% of 456 = 0.21 x 400 + 0.21 x 50 + 0.21 x 6 = 95.76
Step-by-step explanation:
Answer:
It will be an infinite amount, so i think its no solutions
Given :-
- 12 workers can do a piece of work in 20 days .
To Find :-
- How many workers should be added to complete the work in 16 days ?
Solution :-
According to the question ,
→ In 20days 12 workers can do a piece of work.
→ In 1day 12*20 workers can do that work
( Less days , more workers )
→ In 16 days 12*20/16 = 15 workers can do the work.
So 15 -12 = 3 workers should be added to complete the work.
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>3 </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>
