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Grace [21]
3 years ago
12

Write the expression as a single logarithm

Mathematics
1 answer:
viva [34]3 years ago
5 0

We have to use the following log rules here

a log (b) = log b^a  , log(a) + log(b) = log(ab), log (a)-log(b) = log(a/b)

So for the given question , that is

18log \sqrt x +9 log \sqrt [3]{x}-log 10 = log(x^{18/2}) + log(x^{9/3})-log 10

log(x^9)+log(x^3)-log 10= log(x^9*x^3)-log 10

=log(x^{12}) - log 10 = log(\frac{x^{12}}{10})

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2. Chaleah deposited 700$ in a new account that earns 5% simple interest. After 4 years,
Oxana [17]

Answer:

Interest earned: $150.85

Total amount: $850.86

Step-by-step explanation:

Y=700(1.05)^4

Put the right side of the equation into a calculator and get

850.85 that's your total, so to get the amount earned subtract the original 700 from it and get 150.85

5 0
3 years ago
For y=4x-3, find the
Viktor [21]

Answer:

X=5

Step-by-step explanation:

5 0
3 years ago
I need help with this problem plz
VladimirAG [237]

Answer:

<u>x = 18</u>

Step-by-step explanation:

1. Let's solve for x, using the supplementary angles theorem, this way:

∠ C = 180 - 7x + 2 because they are supplementary angles. And these angles add up to 180 degrees.

∠ D = 180 - 9x + 31 because they are supplementary angles. And these angles add up to 180 degrees.

∠ E = 180 - 4x - 33 because they are supplementary angles. And these angles add up to 180 degrees.

Now, let's recall that the interior angles of a triangle add up to 180 degrees. Thus:

∠ C + ∠ D + ∠ E = 180 °

Replacing with the real values for solving for x:

180 - 9x + 31 + 180 - 4x - 33 + 180 - 7x + 2 = 180

- 20 x + 540 = 180

- 20 x = 180 - 540 (Subtracting 540 to both sides)

- 20 x = - 360

<u>x = 18 (Dividing by - 20)</u>

<u>Proving that x = 18 is correct</u>

180 - 9x + 31 + 180 - 4x - 33 + 180 - 7x + 2 = 180

180 - 9 (18) + 31 + 180 - 4 (18) - 33 + 180 - 7 (18) + 2 = 180

180 - 162 + 31 + 180 - 72 - 33 + 180 - 126 + 2 = 180

573 - 393 = 180

180 = 180

<u>We proved that x = 18 is correct</u>

5 0
3 years ago
Simplify the expresion <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B3.%20%5Csqrt%5B4%5D%7B432%7D%20%7D%20" id="TexF
Bond [772]
\sqrt[4]{3. \sqrt[4]{432}}
= \sqrt[4]{3. \sqrt[4]{2^4.3^3} }
= \sqrt[4]{3.2.3^\frac{3}{4}}
= 3^\frac{1}{4}.2^\frac{1}{4}.3^\frac{3}{16}
= 3^\frac{7}{16}.2^\frac{1}{4}



6 0
3 years ago
Please answer fast! (10 points)
SIZIF [17.4K]

Answer:

can u show me a picture of this problem.

Step-by-step explanation:

8 0
3 years ago
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