Hey!
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Solution:
We can get two different ways of 1:6 by add +1:+6.
1 + 1 = 6 + 6
2:12
2 + 1 = 12 + 6
3:18
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Answer:
2:12 and 3:18
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Hope This Helped! Good Luck!
Expected value = -1(1/6) + 2(1/6) + 3(1/6) - 4(1/6) + 5(1/6) - 6(1/6) = -1/6 + 2/6 + 3/6 - 4/6 + 5/6 - 6/6 = -1/6 = -0.167
0.45M+40
The M stands for the amount of minutes he went over.
Answer:
Option A is correct.
Solution for the given equation is, 
Step-by-step explanation:
Given that : 
Let 
then our equation become;
.....[1]
A quadratic equation is of the form:
.....[2] where a, b and c are coefficient and the solution is given by;

Comparing equation [1] and [2] we get;
a = 2 b = -1 and c =-1
then;

Simplify:

or


or
and 
Simplify:
y = 1 and
Substitute y = cos x we have;

⇒
and

⇒
The solution set: 
Therefore, the solution for the given equation
is, 
Answer:
Could you put the questions please?
Step-by-step explanation: