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Svetach [21]
3 years ago
8

Pleases help with 4-9!

Mathematics
1 answer:
Serhud [2]3 years ago
5 0

Step-by-step explanation:

The answer is

4_

m =  \frac{4 - 0}{0 - ( - 2)}  =  \frac{4}{2}  = 2

9_

m =  \frac{3 - 0}{0 - 4}   =  \frac{ - 3}{4}

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Simplify 1 over quantity x minus 3 plus 4 over x all over 4 over x minus 1 over quantity x minus 3
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We can begin this problem by creating a common denominator. our fraction is:

(1/(x-3)+4/x)/(x-1)/(x-3), giving us the common denominator of x(x-3). We then take each individual fraction in the complex fraction, making it so that each one has the denominator x(x-3). 1/(x-3) becomes x/x(x-3), 4/x becomes 4(x-3)/x(x-3), and (x-1)/(x-3) becomes x(x-1)/x(x-3).

Now, our fraction is (x/x(x-3)+ 4(x-3)/x(x-3))/x(x-1)/x(x-3), or simply ((x+4(x-3)/x(x-3))/x(x-1)/x(x-3)). If we multiply the numerator and denominator by x(x-3), we get the fraction (x+4(x+3))/(x(x-1)). 

Distributing the 4, we get (x+4x+12)/(x(x-1)), or (3x+12)/(x(x-1)). (I don't know if you want the denominator factored or not, but if you want it expanded then it's (3x+12)/(x^2-x).)

I hope this was easy enough to follow! I haven't written anything like this before so I'm sorry if it wasn't very good.
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