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damaskus [11]
3 years ago
13

Find the slope of the line perpendicular

Mathematics
1 answer:
siniylev [52]3 years ago
6 0
Ok since your given two points of (-5,2) and origin which is always (0,0) you can find the slope with this formula of y2-y1/x2-x1 plug them in the formula and you should get 0-2/0-5 which is equal to -2/-5 or 2/5 negative signs cancel out now you found your slope but remember the promblem was asking for perpendicular slope to get this you simply flip or reciprocate the slope and take take the opposite sign in our case the slope is 2/5 but the perpendicular version is -5/2 hope this helps.
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Write the decimal expansion for each rational number. a.1/9 b.10/11 c.1 5/27
Contact [7]

Im answering your question bc I need points ty :)

5 0
2 years ago
Will give brainlest answer please help
Tju [1.3M]

Answer:

-1

Step-by-step explanation:

You can do this two ways, the easiest way is to look at the graph.

What is g(4) means: When the x value equals 4, what does y equal?

Look for the coordinate with the x-value of 4 (it's asking for g(4). Now if you look at the y-value of the coordinate, it should tell you what g(4) is. So since the coordinate is (4,-1), g(4) is -1.

Another way to do it is to plug in 4 for x in the equation. So...

g(4) = -[f(4) - 3)]

g(4) = -[4 - 3]

g(4) = -[1]

g(4) = -1

7 0
2 years ago
A rectangle on a coordinate plane has vertices Q(-1, 1), R(6,1), S(6,-8), and T(-1,-8). What are the dimensions of the rectangle
xeze [42]

Answer:

The length is 9.

The width is 7.

Step-by-step explanation:

A rectangle has two dimensions.

The width, which is the distance between the points who have the same value of y.

The length, which is the distance between the points who have the same value of x.

Distance between 2 points:

Points (a,b) and (c,d).

D = \sqrt{(c-a)^{2} + (d-b)^{2}}

Same value of x:

(-1,1), (-1-8) or (6,1), (6,-8)

The distance for both of them is the same, can calculate for only one.

L = \sqrt{(6-6)^{2} + (-8 - 1)^{2}} = \sqrt{81} = 9

The length is 9.

Same value of y:

(-1,1), (6,1) or (6,-8), (-1,-8)

W = \sqrt{(6 - (-1))^{2} + (1 - 1)^{2}} = \sqrt{49} = 7

The width is 7.

6 0
3 years ago
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6 0
3 years ago
Does the following infinite series have a sum or not and does it converge or diverge?
iren [92.7K]

Answer:

Step-by-step explanation:

Please present these numbers as a list:  7, -21, 63, -189, ....

Otherwise it appears that you are adding them up, which is not the case.

We can tell that this is a geometric series because each new number is -3 times the previous number:  -3(7) = -21, -3(-21) = 63, and so on.  Let r = -3 and a = first number = 7.

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The sum of an infinite geometric series exists if and only if |r} < 1.  Here, |-3|, or 3, so in this case the sum of the series does not exist.  That is, the series diverges.

3 0
2 years ago
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