Question

Find the coordinates for the midpoint of the segment with endpoints given. (10, 6) and (-4, 8) (7, 7) (3, 7) (7, 3)

Answer 1

The midpoint of the segment with endpoints (10, 6) and (-4, 8) would be
$\left(\dfrac{10 + -4}2,\dfrac{6 + 8}2\right) = \left(\dfrac{6}2,\dfrac{14}2\right) = \boxed{(3,7)}$

Answer 2

Answer:

Mid point $(3,7)$.

Step-by-step explanation:

Given : End point  (10, 6) and (-4, 8)

To find : Mid point .

Solution : We have given  End point  (10, 6) and (-4, 8)

Mid point : $(\frac{x_{1} +x_{2}}{2},\frac{y_{1} +y_{2}}{2})$.

$x_{1}=10$

$x_{2}=-4$

$y_{1}=6$

$y_{2}=8$.

Then , $(\frac{10 +(-4)}{2},\frac{6 + 8}{2})$.

$(\frac{10 -4}{2},\frac{14}{2})$.

$(\frac{6}{2},\frac{14}{2})$.

$(3,7)$.

Therefore, Mid point $(3,7)$.