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Lady bird [3.3K]
4 years ago
10

A ship traveled for 4 hours heading east and for 3 hours heading north. If the total distance traveled was 149 miles, and the sh

ip traveled 3 miles per hour faster heading north, at what speed was the ship traveling east?
Mathematics
1 answer:
Elina [12.6K]4 years ago
5 0
Just like the previous one

if the ship travelled a total of 149 miles, then let's say it travelled East "d" miles and thus it travelled North the slack of 149 and "d", thus " 149 - d".

now, if the rate travelling East is say "r", then the faster rate going North is " r + 3".

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
East&d&r&4\\
North&149-d&r+3&3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=4r\\
149-d=(r+3)3\\
----------\\
149-\boxed{4r}=3(r+3)
\end{cases}

solve for "r".
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n=-7/2 I hate asking for things but can i have brainliest im trying to rank up.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

n/7−12=5n+5

1/7n+−12=5n+5

1/7n−12=5n+5

Step 2: Subtract 5n from both sides.

1/7n−12−5n=5n+5−5n

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Step 3: Add 12 to both sides.

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Step 4: Multiply both sides by 7/(-34).

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3 0
3 years ago
At a school concert the orchestra plays 8 songs that are 4.25 min long and 3 songs that are twice as long as each of the others.
Orlov [11]

Answer:

Total time of the concert  = 59.5 min =  59 minute 30 seconds

Explanation:

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Total time of the concert = 34 + 25.5 = 59.5 min =  59 minute 30 seconds

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What is the average score of runa 140,96 and 13?​
scoundrel [369]

\huge\textsf{Hey there!}

\large\textsf{Formula:}

\mathsf{\dfrac{Sum\ of\ all\ terms}{Total\ number\ of\ values\ in\ the\ data}= your\ mean/average}

\mathsf{\dfrac{140+96+13}{3}}

\mathsf{140+36+13}

\mathsf{140 + 96 = \bf 236}

\mathsf{236 + 13}

\mathsf{ = \bf 249}

\mathsf{\dfrac{249}{3}}

\mathsf{= \bf 83}

\boxed{\boxed{\large\textsf{Possible answer: \huge \bf 83}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your your day!}

~\frak{Amphitrite1040:)}

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