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vagabundo [1.1K]
3 years ago
14

Computers store temporary Internet files in the Recycle Bin. These files take up space and slow down a computer. Which tool can

be used to remove these unwanted files?
Computers and Technology
1 answer:
poizon [28]3 years ago
6 0
Empty the recycle bin.
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Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y =
Gre4nikov [31]

The brute strength method determines if each x and y value satisfies both conditions. To do this, we must iterate through each result in the specified range and insert them into both models.

<h3>What are Elegant mathematical technique?</h3>

ALGORITHM :

1. Take the values of all coefficients and SET flag = FALSE

2. Run a FOR loop for x in range (-10, 11). 11 won't be included.

2a. Inside the first FOR, start the y FOR loop in range(-10,11). 11 won't be included

2b. Inside the y FOR loop, check IF for a particular value of x and y both the equations satisfied.

2c. If yes, set flag TRUE and print values of x and y.

2d. ELSE the flag stays FALSE.

END FOR Y

END FOR X

3. Check if flag = FALSE, then print NO SOLUTION

PYTHON CODE :

a=int(input()) #taking input for each coefficient

b=int(input())

c= int(input())

a1= int(input())

b1= int(input())

c1= int(input())

flag = False

for x in range(-10,11): #checking for all values of x in range -10 to 10

for y in range(-10,11): #checking for all values of x in range -10 to 10

if (a  x + b  y – c == 0) and (a1*x + b1*y - c1 == 0) : #checking if the x and y values satisfy the equation

flag = True #setting the flag if solution is found

print('Solution : x = {-10, 10}, y = {-10, 10}'.format(x,y)) #if they satisfy print x & y

if flag = False : #if flag stays false, that means there is no solution

print('No solution')

OUTPUT : The output is given below.

More about the Elegant mathematical technique link is given below.

brainly.com/question/27934739

#SPJ1

4 0
2 years ago
in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

6 0
3 years ago
The requester of sensitive information should not receive access just because of his or her clearance, position, or rank. The re
JulsSmile [24]

Answer:

Need to know

Explanation:

Need to know is a policy or predetermined criterion by which the requester of an information is granted access to the requested information only when a valid need is establish and not just because of his or her clearance, position, or rank.  

7 0
3 years ago
Which statement about intellectual property is true? (CSI-7.6) Group of answer choices It is okay to use code you find on the in
nika2105 [10]

Answer:

Laws are in place to cover your creative work, which includes code you have written.

Explanation:

Copyright law can be defined as a set of formal rules granted by a government to protect an intellectual property by giving the owner an exclusive right to use while preventing any unauthorized access, use or duplication by others.

A copyright can be defined as an exclusive legal right granted to the owner of a creative work (intellectual property) to perform, print, record, and publish his or her work. Also, the owner is granted the sole right to authorize any other person to use the creative work.

For instance, copyright law which protects the sharing and downloading rights of music is known as the Digital Millennium Copyright Act (DMCA).

An intellectual property can be defined as an intangible and innovative creation of the mind that solely depends on human intellect.

Simply stated, an intellectual property is an intangible creation of the human mind, ideas, thoughts or intelligence. They include intellectual and artistic creations such as name, symbol, literary work, songs, graphic design, computer codes, inventions, etc.

Hence, laws are in place to cover a person's creative work, and it includes code he or she have written.

6 0
2 years ago
which option of the AutoCorrect tool enables you to add and delete words that do not follow abbreviation rules?
quester [9]

The replace text as you type is an option in the AutoCorrect tool that enables the user to add or delete words that do not follow abbreviation rules. Moreover, this is a convenient way to use especially if you are dealing with long string of words that only needs abbreviation.

3 0
3 years ago
Read 2 more answers
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