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777dan777 [17]
3 years ago
5

If you wish to maintain a consistent style to all the documents you create, it would be helpful to use a _​

Computers and Technology
1 answer:
kakasveta [241]3 years ago
7 0

Answer:Apply a consistent look across the whole document instead of having to format each section individually.Automatically number section headers.Apply same font to the entire text body.Apply the same font to header sections.Use a consistent paragraph spacing.Pick a default color scheme for SmartArt, charts, and shapes.Pick from a number of pre-designed styles use them as your own and modify them.

Read more on Webcache.googleusercontent.com - https://webcache.googleusercontent.com/question/1639566#readmore

Explanation:

tht is the answer

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Which of the following is the final fate for average sized stars?
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Black holes correct.......
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3 years ago
Imagine that you have access to a class named MyCircle that has void setRadius(double r) and double getRadius() methods. Write a
Nikitich [7]

Code for the method described in the question in java:

public static double averageRadius(MyCircle[] myCircles) {

       double sum = 0;

       for (MyCircle myCircle: myCircles) {

           if(myCircle.getRadius() < 0) myCircle.setRadius(0);

           sum += myCircle.getRadius();

       }

       return sum / myCircles.length;

   }

And the complete program:

import java.util.Random;

public class MyCircle {

   private double radius;

   public double getRadius() {

       return radius;

   }

   public void setRadius(double radius) {

       this.radius = radius;

   }

   public static double averageRadius(MyCircle[] myCircles) {

       double sum = 0;

       for (MyCircle myCircle: myCircles) {

           if(myCircle.getRadius() < 0) myCircle.setRadius(0);

           sum += myCircle.getRadius();

       }

       return sum / myCircles.length;

   }

   public static void main(String[] args) {

       Random random = new Random();

       int N = 10;

       MyCircle[] myCircles = new MyCircle[N];

       for (int i = 0; i < myCircles.length; i++) {

           myCircles[i] = new MyCircle();

           myCircles[i].setRadius(random.nextInt(100));

           System.out.printf("Created MyCircle %d with radius %.2f \n", i, myCircles[i].getRadius());

       }

       System.out.printf("\nAverage radius of %d circles is %.2f \n", N, MyCircle.averageRadius(myCircles));

   }

}

The output was:

Created MyCircle 0 with radius 76.00

Created MyCircle 1 with radius 86.00

Created MyCircle 2 with radius 38.00

Created MyCircle 3 with radius 4.00

Created MyCircle 4 with radius 8.00

Created MyCircle 5 with radius 39.00

Created MyCircle 6 with radius 77.00

Created MyCircle 7 with radius 78.00

Created MyCircle 8 with radius 39.00

Created MyCircle 9 with radius 46.00

Average radius of 10 circles is 49.10

7 0
3 years ago
Recall the binary search algorithm.1. Using the algorithm/algorithmic environment, give pseudocode using a for loop.AnswerMy alg
faust18 [17]

Answer:

Following are the Pseudo Code to the given question:

Explanation:

Following are the pseudo-code by using the For loop:

Defines the A function (node, element)

The node is larger than 0.

if another value of the node equals its element

Loop Break

That element if node. value becomes lower than that

Node is node equivalent.

right

Using other nodes is node equivalent.

 left

Node Return

If the node is vacant

print the Tree is empty

Following are the pseudo-code by using the while loop:

Defines the function A(node,element)

While this node is not zero.

if the value of the node equals the element

Loop Break

The element if node. value is lower than

Node is node equivalent.

right

Using other nodes is equivalent to an a.left node

Node Return

If the node is vacant

print Tree is empty

following are the Pseudo-code for recursion:

Set the function A (node, key)

If no root is the same as the root or no root.

return the root.

If the root value is lower than that of the quest for key return (root. right, key)

Return your lookup (root.left,key)

 

5 0
3 years ago
Each character in a string has a(n) _______________ which specifies its position in the string.
-BARSIC- [3]
<span>The string is a sequence of characters.</span><span>
Each character in a string has an index which specifies its position in the string.
</span>The index of the first character is 0, the second character is 1, and so on.The character at the nth position has the index n.

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3 years ago
The sales of last 6 months are stored in a list,
MissTica

list1 = [12500, 35000, 12000, 40000, 55000,60000]

print(sum(list1)/len(list1))

We take the sum of all the elements in the list and divide the sum by the quantity of the elements. You can put however many elements in this list and you'll always get the average using the algorithm above.

6 0
3 years ago
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