First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
The domain is (-3,0) U (2,4)
The range is (-2,-1) U (1,2)
Answer:
<h2>
Reflection across the y-axis and 1 unit shift downside.</h2>
Step-by-step explanation:
Notice that shape A is in the second quadrant and shape B is in the first quadrant. That means there was a reflection across y-axis and then the figure was shifted one unit downside.
Therefore, the transformation was reflection across the y-axis and 1 unit shift downside. Which is a rigid transformation, because the shape and size didn't change.
Zero Property of Multiplication hope this helps
Answer:6
4 multiplied by 6 is 24 so 6 is the answer
