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ch4aika [34]
3 years ago
12

Solve. Check for extraneous solutions

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

This equation has no solutions on the real-valued logarithm.

Step-by-step explanation:

Raise both sides to the 8th power:

11-6x = 1-x

10 = 5x

x = 2

Plug this in:

log(11 - 6(2)) = log(11 -12) = log(-1); this is NOT a valid solution on a real-valued logarithm.

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A rectangular garden is fenced on all sides with 256 feet of fencing. The garden is 8feet longer than it is wide. Find the lengt
Marina86 [1]
Perimeter = 2L + 2W = 256

"8 feet longer than it is wide"
translates to
L = 8 + W

we plug that into the first equation and get
2(8 + W) + 2W = 256
now we solve for W

distribute the 2
16 + 2W + 2W = 256

add like terms
16 + 4W = 256

subtract 16 from both sides
4W = 240

divide both sides by 4
W = 60

plug that into
L = 8 + W
and solve for L now

L = 8 + 60
so
L = 68

therefore your
length = 68
and
width = 60
6 0
3 years ago
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Answer:

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6 0
3 years ago
Answer the circled question
Wittaler [7]

Answer:

Length = 6 cm    Breadth = 5 cm

Step-by-step explanation:

All I did was find the factors of 30, and look out for the one that also equals 22 when added. 5+5+6+6=22,  5x6=30.

4 0
4 years ago
I just need the answer bru why’s it gotta Make write 20 words‍♂️ this is dumb as hell bru‍♂️
TiliK225 [7]

Answer:

11

Step-by-step explanation:

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9=?-2

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5 0
4 years ago
A square sheet of art paper has an area of 625 square inches. What is the minimum side length of an easel that supports the whol
Mila [183]
If the area of the paper is 625 sq in, the length of one side of this square is sqrt(625 sq in), or 25 inches.  That's the min. side length of an easel that is to support the whole sheet of paper along its lowest side.
7 0
3 years ago
Read 2 more answers
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