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ch4aika [34]
3 years ago
12

Solve. Check for extraneous solutions

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

This equation has no solutions on the real-valued logarithm.

Step-by-step explanation:

Raise both sides to the 8th power:

11-6x = 1-x

10 = 5x

x = 2

Plug this in:

log(11 - 6(2)) = log(11 -12) = log(-1); this is NOT a valid solution on a real-valued logarithm.

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