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2 years ago

What number is 1.6 more than 3.7

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

7 0

Answer: 5.3

Step-by-step explanation: To solve this question, all you need to do is add the numbers together. 1.6+3.7=5.3

Feliz [49]2 years ago

5 0

Answer:

the answer is5.3

Step-by-step explanation:

3.7+1.6=5.3

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Solve for y in 7y - 3/4 = -1/4y - 1/3

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Answer for y is y=5/87

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2 years ago

Melinda said that the fort would melt in the fourth month of the year. What month will the fort melt?

yaroslaw [1]

Answer:

april

Step-by-step explanation:

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2 years ago

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mr sanchez owns a square field. the side lengths are 0.9 kilometers. there are 1980 prairie dog burrows in the field. what is th

nata0808 [166]

Density is the measurement of the amount of mass per unit of volume.
In this case we should calculate the density of prairie dog burrows on a square field. This is a surface charge density.It is defined as the total amount of units q per km^2.
to calculate the density of prairie dog burrows, we should divide the total number of prairie dog burrows in the field by the size of the field. Thus,

prairie dog burrows in square kilometers= number of dog burrows/ size of the field

size of the field=0.9*0.9=900*900=180000m^2
1980/180000 m^2= 0.011 dog burrows in square meter
11 dogs in square kilometer

5 0

2 years ago

A ball dropped from the top of a building can be modeled by the function f(t)=-16^2+36, where t represents time in seconds

Viefleur [7K]

Answer:

The ball is dropped from a height of 36 feet

The bee and the ball will collide after approximately 1.3 seconds

The bee and the ball will collide at approximately 8 feet above the ground

The ball hits the ground after 1.5 seconds

Step-by-step explanation:

The complete question is

A ball dropped from the top of the building can be modeled by the function f(t)=-16t^2 + 36 , where t represents time in seconds after the ball was dropped. A bee's flight can be modeled by the function, g(t)=3t+4, where t represents time in seconds after the bee starts the flight.

The graph represents the situation.

select all that apply

1) The bee launches into flight from the ground.

2) The ball is dropped from a height of 36 feet.

3) The bee and the ball will collide after approximately 1.3 seconds.

4) The bee and the ball will collide after approximately 8 seconds.

5) The bee and the ball will collide at approximately 8 feet above the ground.

6) The bee and the ball will not collide.

7) The ball hits the ground after 1.5 seconds

see the attached figure to better understand the problem

Verify all the options

case 1) The bee launches into flight from the ground.

The statement is false

Because

we have

$g(t)=3t+4$

For t=0

$g(t)=3(0)+4=4\ ft$

That means ----> The bee launches into flight from a height 4 feet above the ground

case 2) The ball is dropped from a height of 36 feet

The statement is true

Because

For t=0

$f(t)=-16(0)^2+36=36\ ft$

case 3) The bee and the ball will collide after approximately 1.3 seconds

The statement is true

Because

Equate f(t) and g(t)

$-16t^2+36=3t+4$

$-16t^2-3t+32=0$

solve the quadratic equation by graphing

The solution is t=1.324 sec

see the attached figure N 2

case 4) The bee and the ball will collide after approximately 8 seconds

The statement is false

Because, the bee and the ball will collide after approximately 1.3 seconds (see case 3)

case 5) The bee and the ball will collide at approximately 8 feet above the ground

The statement is true

Because

For t=1.324 sec

substitute the value of t in f(t) or g(t)

$g(t)=3(1.324)+4=7.97\ ft$

case 6) The bee and the ball will not collide

The statement is false

see case 3) and case 5)

case 7) The ball hits the ground after 1.5 seconds

The statement is true

Because

we know that

The ball hit the ground when the value of f(t) is equal to zero

For f(t)=0

$-16t^2+36=0$

$t^2=\frac{36}{16}$

$t=\frac{6}{4}=1.5\ sec$

4 0

2 years ago

Read 2 more answers

Somebody please help

DENIUS [597]

What you want to do, is isolate the y by itself to rewrite the equation as y=mx+b. So when you move the 5x over the equation looks like this -6y=-5x+30. Then you divide the -5x+30 by -6 to isolate the y. Thus making the equation y=5/6x-5. And since there is only one answer with the y-intercept as (0,-5); The answer is A.

8 0

2 years ago