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mr Goodwill [35]
3 years ago
10

A sled is initially given a shove up a frictionless 28.0 degree incline. It reaches a maximum vertical height 1.35m higher than

where it started. What was the initial speed?
Mathematics
1 answer:
QveST [7]3 years ago
8 0
The problem ask to calculate the initial speed of the sled that was shove up a frictionless 28 degree incline and reaches a maximum vertical height of 1.35 m than it started and the initial speed of the sled is 5.14 m/s. I hope you are satisified with my answer 
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SpyIntel [72]
Try this option:
note, that distance between the parallel sides is shown via formula of area.
If it is possible, check the arithmetic.

5 0
3 years ago
Read 2 more answers
( BRAINLIEST AND THANKS! )
Kamila [148]

Answer:

Step-by-step explanation:

X Y

--------

1 0.50

2 0.25

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3 0
2 years ago
Plz..... Solve this questions for me...
faust18 [17]

6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================

7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================

8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10

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2 years ago
A right triangle has side lengths of 4 unit's, 5 unit's and x units. It is unkown If the missing length is the longest or shorte
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If x is the hypotenuse then
hyp^2 = 4^2 + 5^2
hyp^2 = 41
hypotenuse = <span> <span> <span> 6.403124

</span></span></span>
if x is a leg then
leg^2 = 5^2 - 4^2
leg^2 = 25 - 16
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8 0
3 years ago
Can someone plzz help​
tankabanditka [31]

Answer:

it's 12 because

2×6=12

3×4=12

4×3=12

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6 0
3 years ago
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