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3 years ago

Determine the 20th term of the sequence: -14,-8, -2, 4, 10,

Mathematics

1 answer:

Pie3 years ago

3 0

Answer: The 20th term is 100

Step-by-step explanation: It adds by 6 each time

-14, -8, -2, 4, 10, 16, 22, 28, 34, 40, 46, 52, 58, 64, 70, 76, 82, 88, 94, 100

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Use the triangles Name one pair of congruent angles.

Likurg_2 [28]

Your correct answer is option B

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3 years ago

From families with four children a family is chosen at random. Let X be the number of boys in the family. Calculate and sketch t

alisha [4.7K]

Solution :

Given :

X = the number of boys in a family of four children

Families having four children are chosen randomly.

The gender distribution in the four child family are equally probable.

Thus,

X P(X) CDF

0 $^4C_0 (1/2)^{4}$ = 1/16 $\frac{1}{16}$

1 $^4C_1 (1/2)^{4}$ = 1/4 $\frac{5}{16}$

2 $^4C_2 (1/2)^{4}$ = 3/8 $\frac{11}{16}$

3 $^4C_3 (1/2)^{4}$ = 1/4 $\frac{15}{16}$

4 $^4C_4 (1/2)^{4}$ = 1/16 1

4 0

3 years ago

Find the quotient 4/3÷1 1/12

nlexa [21]

The answer should be 1/9

8 0

2 years ago

SOLVE CORRECTLY AND SHOW WORKKKK!

nadya68 [22]

Answer:

50=(3x)x

Step-by-step explanation:

50=(3x)x. The question is only asking for the inequality of the problem. Since the area of a rectangle is L x W, you would write L as 3x and W as x, and since the area of the rectangle is given, you can set the area as 50.

3 0

1 year ago

Read 2 more answers

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

3 years ago