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yarga [219]
3 years ago
13

17. The length of a swing is 2.1 m. If the length

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

dose it tell you want angle the arc is at?

Step-by-step explanation:

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Kevin is 333 years older than Daniel. Two years ago, Kevin was 444 times as old as Daniel.
tia_tia [17]

Answer: the equations are

k = d + 33

k - 2 = 4(d-2)

Step-by-step explanation:

Let the present age of Kevin be represented by k

Let the present age of Daniel be represented by d

Kevin is 33 years older than Daniel. This means that the expression for their current age is

k = d + 33

Two years ago, Kevin was 4 times as old as Daniel. This means that 2 will be subtracted from their present ages to depict two years ago. Therefore, Two years ago for Daniel will be d-2

Two years ago for Kevin will be k - 2

Remember that Kevin was 4 times as old as Daniel two years ago, it becomes

k - 2 = 4(d-2)

5 0
3 years ago
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IceJOKER [234]

Answer: 8. 3^4+n^4, 9. 7^3+m^4, and 10. s+2t^3.

Step-by-step explanation:

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3 years ago
According to the Census Bureau, in 2014 California had an estimated population of 3.88 x 10^7 and Wyoming had an population of 5
Verdich [7]
The population of California is 3.88 x 10^7 - 5.84 x 10^5 = 3.82 x 10^7 more than the population of Wyoming. Alternatively the population of California is 3.88 x 10^7 / 5.84 x 10^5 = 66 times the population of Wyoming. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
8 0
3 years ago
The first term of an arithmetic sequence is -5, and the tenth term is 13. find the common difference
Vilka [71]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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