Question

Kevin is 333 years older than Daniel. Two years ago, Kevin was 444 times as old as Daniel.

Answer 1

Answer: the equations are

k = d + 33

k - 2 = 4(d-2)

Step-by-step explanation:

Let the present age of Kevin be represented by k

Let the present age of Daniel be represented by d

Kevin is 33 years older than Daniel. This means that the expression for their current age is

k = d + 33

Two years ago, Kevin was 4 times as old as Daniel. This means that 2 will be subtracted from their present ages to depict two years ago. Therefore, Two years ago for Daniel will be d-2

Two years ago for Kevin will be k - 2

Remember that Kevin was 4 times as old as Daniel two years ago, it becomes

k - 2 = 4(d-2)

Answer 2

Answer: $k= d+3$

$k-2 = 4(d-2)$

Step-by-step explanation:

Let k be Kevin's age and Let d be Daniel's age.

Given : Kevin is 3 years older than Daniel.

i.e. Age of Kelvin = Age of Daniel+ 3

i.e.  In terms of variables , k= d+3                  (1)

Two years ago,

Age of Kelvin =  k-2

Age of Daniel = d-2

Since Two years ago ,Kevin was 4 times as old as Daniel.

i.e.  In terms of variables  : $k-2 = 4\times(d-2)$      

$k-2 = 4(d-2)$            (2)

From (1) and (2) the system of equations represents this situation are

$k= d+3$

$k-2 = 4(d-2)$