Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).
1 answer:
Answer:
(x +1)^2 +(y +0.5)^2 = 22.25
Step-by-step explanation:
The center of the circle is the midpoint of the diameter, so is ...
(h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)
The circle formula is then ...
(x -h)^2 +(y -k)^2 = r^2
(x -(-1))^2 +(y -(-1/2))^2 = r^2
We can find r^2 by substituting one of the points for (x, y).
(3 +1)^2 +(2 +1/2)^2 = r^2 = 16 +6.25 = 22.25
Then the circle equation is ...
(x +1)^2 +(y +0.5)^2 = 22.25
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Answer:
1. 144 2. 16 3. 1 4. 3x-6
Step-by-step explanation:
So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).
Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]
so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)
So take the h(x) function which is h(x) = then h(12) =
so h(12) = 144