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Degger [83]
3 years ago
12

Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

  (x +1)^2 +(y +0.5)^2 = 22.25

Step-by-step explanation:

The center of the circle is the midpoint of the diameter, so is ...

  (h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)

The circle formula is then ...

  (x -h)^2 +(y -k)^2 = r^2

  (x -(-1))^2 +(y -(-1/2))^2 = r^2

We can find r^2 by substituting one of the points for (x, y).

  (3 +1)^2 +(2 +1/2)^2 = r^2 = 16 +6.25 = 22.25

Then the circle equation is ...

  (x +1)^2 +(y +0.5)^2 = 22.25

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QveST [7]
Just add up all the numbers
7 0
3 years ago
Solve ABC <br>c=10, B=35°, C=65%​
NISA [10]

Answer:

Part 1) The measure of angle A is A=80\°

Part 2) The length side of a is equal to a=10.9\ units

Part 3) The length side of b is equal to b=6.3\ units

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

A+35\°+65\°=180\°

A+100\°=180\°

A=180\°-100\°=80\°

step 2

Find the length of side a

Applying the law of sines

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}

a=\frac{10}{sin(65\°)}(sin(80\°))

a=10.9\ units

step 3

Find the length of side b

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

substitute the given values

\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}

b=\frac{10}{sin(65\°)}(sin(35\°))

b=6.3\ units

5 0
3 years ago
The circumference is 12 mile. What is the diameter?
photoshop1234 [79]

To find the diameter of a circle, using only the circumference, you need to divide the circumference by π, or 3.14.

So in this case, you must divide 12 by 3.14, which gives you 3.82.

I even double checked this, and should be correct then.

8 0
2 years ago
Read 2 more answers
Complete parts a through c for the given function.
victus00 [196]

Answer:

a. The critcal points are at

x=0,-5,3

b. Then, x = -5   is a maximum and x=3 is a minimum

c. The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

Step-by-step explanation:

(a)

Remember that you need to find the points where

f'(x)=0

Therefore you have to solve this equation.

20x^4  + 40x^3 - 300x^2 = 0

From that equation you can factor out    20x^2  and you would get

20x^2 (  x^2  +2x - 15)  = 0

And from that you would have   20x^2 = 0  , so x = 0.

And you would also have  x^2 +2x-15 = 0.

You can factor that equation as    x^2 +2x -15 = (x+5)(x-3) = 0

Therefore   x=-5 ,   x=3.

So the critcal points are at

x=0,-5,3

b.  

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\

Then, x = -5   is a maximum and x=3 is a minimum

c.

The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

6 0
3 years ago
Read 2 more answers
QUICK!! TEN POINTS!! BRAINLIEST FOR WHOEVER GETS IT RIGHT!!
lara [203]

Answer:

(-2, -4.5)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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