1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LiRa [457]
3 years ago
13

Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)

vxe D, if x is odd then x> 0 [Select] b) vx e D, if x is less than 0 then x is even [Select] c) VXe D, if x is even then xs0 [Select] d) vx e D, if the ones digit of x is 2, then the tens digit is 3 or 4 e) VX e D, if the ones digit of x is 6, then the tens digit is 1 or 2 [Select]
Mathematics
1 answer:
morpeh [17]3 years ago
8 0

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

You might be interested in
Help!! i cannot figure this out
Debora [2.8K]

Answer:

A. 12 miles

B. 9 miles

C. 2 hours

D. 5 hours

E. Max did not move

F. 9 hours

G. 5 hours

hope this helps :)

Step-by-step explanation:

4 0
2 years ago
Can someone answer part B for me? Thank you and will give brainliest.
frez [133]

Answer:

The answer to part B is B.

Step-by-step explanation:

Could you take another photo so I can see the bottom of the page?

4 0
3 years ago
PLEASE HELP!!<br><br> which graph represents the function f(x) = -|x| - 2
Nonamiya [84]

Answer:

The graph on the far right

Step-by-step explanation:

The negative in front of the absolute value indicates that the parent function |x| has been reflected over the x-axis and points downwards. The negative 2 being added to this portion shows that there has been a vertical shift of two units downwards as well. Therefore, the graph on the far right is the correct graph.

4 0
2 years ago
PLEASE HELP WITH NUMBER 5 use the graph above for the answer
jenyasd209 [6]
You answer is false because the 25 is almost equal to 28 have a nice day
6 0
2 years ago
How to find the θ in this equation: tan(θ+16°)=1/tan(θ+60°) by using the trigonometric identities?thanks
DedPeter [7]

Answer:

\huge \theta  =7°

Step-by-step explanation:

tan( \theta + 16 \degree) =  \frac{1}{tan( \theta + 60 \degree) }  \\ tan( \theta + 16 \degree) =cot( \theta + 60 \degree) \\ tan( \theta + 16 \degree) = tan \{90 \degree - (\theta + 60\degree) \} \\ \theta + 16 \degree = 90 \degree - \theta  -  60\degree \\ \theta +\theta  = 30 \degree - 16\degree \\2 \theta  = 14 \degree  \\ \theta  =  \frac{14 \degree}{2}   \\   \huge \red{ \boxed{\theta  =7 \degree}}

7 0
3 years ago
Other questions:
  • Find the area of this rhombus
    9·2 answers
  • Find all solutions of each equation on the interval 0 ≤ x &lt; 2 pi.
    5·1 answer
  • 31.24 to 1 decimal place
    15·1 answer
  • 6[12-(5+2)]+6(4•|-6|)​
    11·2 answers
  • Can someone plz plz plz help me?????
    11·1 answer
  • If three quarters of a certain number is 48 find the number​
    14·1 answer
  • What is the additive inverse​
    6·1 answer
  • What number is 0.4% of 40<br><br><br> Thank you so much
    9·1 answer
  • Through: (3,0), parallel to y = 2/3x+1
    10·1 answer
  • 18
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!