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il63 [147K]
3 years ago
5

A company employee is planning a promotion party with her friends. She orders 6 pizzas for $7 each, 2 bowls of mixed salad for $

12 each, and 4 cases of assorted soft drinks for $5 each. How much is she spending on the party?
Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

$86 is she spending on the party.

Step-by-step explanation:

As per the statement: A company employee is planning a promotion party with her friends. She orders 6 pizzas for $7 each, 2 bowls of mixed salad for $12 each, and 4 cases of assorted soft drinks for $5 each.

⇒ 6 pizzas for $7 each

Total cost for 6 pizzas = 6 \times 7 = \$42

2 bowls of mixed salad for $12 each.

Total cost for 2 bowls = 2 \times 12 = \$24

and

4 cases of assorted soft drinks for $5 each.

Total cost for 4 cases of assorted soft drinks = 4 \times 5 = \$20

She spending on party = Total cost for 6 pizzas + Total cost for 2 bowls + Total cost for 4 cases of assorted soft drinks

Substitute the values we get;

Total cost she spending on party = \$42 + \$24 + \$20 =\$86

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\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

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