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vovikov84 [41]
2 years ago
11

why do whole numbers raised to an exponent get greater while fractions raised to an exponent get smaller?

Mathematics
2 answers:
ehidna [41]2 years ago
8 0
Any number above 1 gets greater, below 1 smaller (when above 0), while 1 itself remains the same. Negative numbers are more unpredictable.
8_murik_8 [283]2 years ago
8 0

Answer:

Because whole numbers are greater than 1 and any number greater than 1 multiplied by it self several times result in a greater number, but proper fractions are numbers less than 1, and a number less than 1 multiplied by it self several times result if a smaller number.

Explanation:

Whole numbers are raised to an exponent , means that such number is multiplied by itself (as many times and the exponent is).

Whole numbers are 1, 2, 3, 4, ....

Number 1 is a special case. When 1 is multiplied by it self the result is 1.

When other whole number (2, 3, 4, 5, ...) is multiplied by it self the result is a greater number. For example, 2 × 2 = 4, 3 × 3 = 9, and so on.

On the other hand, proper fractions, which are those whose numerator is less than the denominator, are less than one, and any number less than 1 multiplied by it self results in a smaller number.

For example: 1/2 × 1/2 = 1/4 or 0.5 × 0.5 = 0.25. This is always true for any proper fraction (a number less than 1).


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3 years ago
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olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

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First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

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The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

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0 = 16a + 4 and

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Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

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