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romanna [79]
3 years ago
8

Plis help with this. - - -

Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer: 16

Step-by-step explanation:

multiplying by negative exponents can be a little tricky. So (1/4x)^-2 becomes 16/x^2 = __/x^2 so the missing number is 16

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What number would you multiply the 1st equation by to eliminate y? -4x - y = -11 -6x - 3y= -27
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Multiply 1st equation by 3

Step-by-step explanation:

To eliminate -3y, we must multiply the 1st equation by such a number that the -y becomes -3y. This can be done by multiplying the 1st equation by 3.

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Is 1 = 2 always a false statement?
lutik1710 [3]

Answer:

yes, 1 can never equal 2 unless it is manipulated (ex: 1(2) = 2)

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5 0
3 years ago
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If the discriminant is positive how many solutions are there
ddd [48]

Answer:

b^2-4ac>0 yields 2 real roots

Step-by-step explanation:

To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.

• b^2-4ac>0 yields 2 real roots

• b^2-4ac=0 yields 1 real root

• [tx]b^2-4ac<0[/tex] yields no real roots

Example:

4x^2-7x+2=0 where a=4, b=-7, and c=2

b^2-4ac=(-7)^2-4(4)(2)=49-32=17.

It has 2 real roots


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