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3 years ago

Anyone? please? i need help, i dont understand how to do this

Mathematics

1 answer:

Afina-wow [57]3 years ago

8 0

Answer:

a. A(0) is $2500 and A(10) is $3700.61

b. The beginning value and the value after ten years

c. 17.673 years

d. That after roughly 17 and a half years, his investment will be doubled.

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Coke is creating a smaller version of the 12 ounce coke. If they use a scale factor of 0.75, how many ounces will be in the new

Dvinal [7]

It WILL Be 9 Ounces Bro

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3 years ago

Which of these is an exponential parent function? OA. f(x)=2x-2 OB. f(x) = 2x C. f(x) = 2x + 3 OD. f(x) = 24x

melomori [17]

The answer to this question is choice B

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1 year ago

PLEASE HELP ME WITH THIS QUESTION AND ILL BRAINLIEST YOU

neonofarm [45]

Answer:

Step-by-step explanation:

Two sum of any two side lengths of a triangle will always be greater than the length of the remaining side

a doesn't work because 8+12=20 and 20 is not greater than 20

b doesn't work because 4+5=9 and 9<10

d doesn't work because 6+6=12 and 12 is not greater than 12

c is the only option where you can take any two sides, add them, and the sum will be greater than the remaining side.

For example, for c,

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8+10=18, and 18>6

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7 0

3 years ago

Read 2 more answers

35/8 + 10/3 = simplest form

Nimfa-mama [501]

Answer:

185/24

Step-by-step explanation:

Convert both to fractions with the same denominator first.

35/8= 105/24

10/3= 80/24

105/24+80/24

= 185/24

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3 years ago

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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

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3 years ago