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Ira Lisetskai [31]

3 years ago

12

3x-2y=13 2x+3y=-16 are these lines parallell or perpendicular or neither

1 answer:

Lelechka [254]3 years ago

6 0

3x - 2y = 13
-2y = -3x + 13
y = 3/2x - 13/2...slope is 3/2, y int is -13/2

2x + 3y = -16
3y = -2x - 16
y = -2/3x - 16/3...slope = -2/3, y int is -16/3

perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, flip the number and change the sign.
On the 1st equation, the slope was 3/2....find its negative reciprocal.....flip it, making it 2/3....change the sign...making it -2/3. So the negative reciprocal of 3/2 is -2/3.

So if one equation has a slope of 3/2 and another equation has a slope of -2/3, then these lines are perpendicular <==

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Use the Associative Property of Addition to write an expression equivalent to (n + 2) + 7. Which expression is equivalent to (n

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Answer:

The correct answer is OB.

Step-by-step explanation:

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3 years ago

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Alisiya [41]

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4 0

3 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago