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erma4kov [3.2K]
4 years ago
8

In the figare, Linet Intersects parallel Lines m and n.

Mathematics
1 answer:
otez555 [7]4 years ago
5 0

Answer:

B.

Step-by-step explanation:

<2 and <3 are vertically opposite angles and are also congruent. Both the angles are hence called vertical angles.

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(?,6) is on the line 2x – 7y = 0. What is the other half of the coordinate
yarga [219]
If we plug the given value of y = 6 into the equation, we get:
2x-7\times6=0
which can be rearranged to
2x = 42
giving x = 21.
Therefore the other half of the coordinate is 21.
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3 years ago
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Pls hyelp. Me needs hyelp palease . Preciate it. Hehehehehehehehehe
klio [65]

Answer:

Step-by-step explanation:

You want to factor out perfect squares if they exist.

1.\ \sqrt{36}=\sqrt{6^2}=6\\ \\ 2.\ \sqrt{40}=\sqrt{2^2(10)}=2\sqrt{10}\\ \\ 3.\ \sqrt{75}=\sqrt{3(5^2)}=5\sqrt{3}\\ \\ 4.\ \sqrt{120}=\sqrt{2^2(30)}=2\sqrt{30}\\ \\ 5.\ \sqrt{84}=\sqrt{2^2(21)}=2\sqrt{21}\\ \\ 6.\ \sqrt{48}=\sqrt{4^2(3)}=4\sqrt{3}

4 0
3 years ago
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A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
lana [24]

Answer:

(9)\frac{1}{12}  (10) \frac{1}{12}  (11)\frac{5}{12}  (12)\frac{1}{4}  (13)\frac{1}{6} 14)\frac{5}{36} (15)\frac{1}{12}  (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are:  (3, 6), (4, 5),  (5, 4)

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are:  (1, 3),(2, 2),(3, 1),

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4),  (3, 1), (3, 2), (3, 3),  (4, 1), (4, 2),  (5, 1)

P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6),  (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4),  (5, 5), (6, 6)

P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5),  (3, 4), (4, 3), (5, 2),  (6, 1)

P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}

16.Probability of getting two numbers with a sum of 14.

P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0

4 0
4 years ago
According to a 2015 Census Bureau survey, 75,511 of the 822,959 residents of Baltimore County, Maryland, were enrolled in colleg
quester [9]

Answer:

73.4

Step-by-step explanation:

-Given that 75,511 out of 822,959  residents enrolled in the college, the probability of success  is calculated as:

P_{enrollment}=\frac{Enrollment}{Total \ Residents}\\\\=\frac{75511}{822959}\\\\=0.09176\\\\p=0.09176

#We know that this is a binomial distribution with p=0.09176 and n=800, Expected value is calculated as:

E(X)=np, n=800, p=0.09176\\\\=0.09176\times 800\\\\=73.4

Hence the expected value E(X)=73.4

6 0
4 years ago
(x-6)(x+2) hi am am stuck can someone answer asap
notka56 [123]

Answer:

x²-4x-12

Step-by-step explanation:

multiply each term in the first parentheses by each term in the second parentheses

x*x+2x-6x-6*2

calculate the product

x²+2x-6x-12

collect like terms

x²-4x-12

7 0
3 years ago
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