To which set of real numbers does the following number belong?

Mathematics

2 answers:

strojnjashka [21]3 years ago

7 0

Irrational would be the right answer!

Sever21 [200]3 years ago

4 0

Discussion

A whole number is a counting number. 2 5 29 44 18 are all counting numbers. They have no decimals trailing after them. C is not the answer.

An imaginary number is one like 18i where i is the square root of - 1. Nothing in our number system will give the square root of - 1 so we have to define that condition into our number system. i * i = - 1. So by definition and definition alone i is the square root of - 1. Those are called imaginary numbers because they are defined.

A rational number can be expressed as a fraction. It does not matter what kind of fraction. It is just a fraction. 3 1/3 = 10/3 That's a rational number. 14/7 is also rational.

sqrt(3) is irrational. It has an endless line of decimal places that have no pattern. 1/7 = 0.142857 ... repeating. But it is rational even though the decimal goes on forever. If I tell you the 70th place is a 5, I can tell you that the next digit will by a 7 [The 5 may not be true].

No such statement can be made about sqrt(3).

Answer: irrational.

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fgiga [73]

Answer:

$\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.$

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

$\qquad\boxed{\sf Area_{(square)}= side^2}$

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

$\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}$

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

$\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x \\\\\sf\implies x = \dfrac{ b}{3}$

$\rule{200}2$

Hence the TSA of cuboid in terms of lenght and breadth is :-

$\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}$