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8090 [49]
3 years ago
12

To which set of real numbers does the following number belong?

Mathematics
2 answers:
strojnjashka [21]3 years ago
7 0

Irrational would be the right answer!


Sever21 [200]3 years ago
4 0

Discussion

A whole number is a counting number. 2 5 29 44 18 are all counting numbers. They have no decimals trailing after them. C is not the answer.

An imaginary number is one like 18i where i is the square root of - 1. Nothing in our number system will give the square root of - 1 so we have to define that condition into our number system. i * i = - 1. So by definition and definition alone i is the square root of - 1. Those are called imaginary numbers because they are defined.

A rational number can be expressed as a fraction. It does not matter what kind of fraction. It is just a fraction. 3 1/3 = 10/3 That's a rational number. 14/7 is also rational.

sqrt(3) is irrational. It has an endless line of decimal places that have no pattern. 1/7 = 0.142857 ... repeating. But it is rational even though the decimal goes on forever. If I tell you the 70th place is a 5, I can tell you that the next digit will by a 7 [The 5 may not be true].

No such statement can be made about sqrt(3).

Answer: irrational.

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19 + x/2 = 4<br> How do I do this
GuDViN [60]

Answer: x = -30

Steps:  19 + x/2 = 4

Subtract 19 from both sides: 19 + x/2 - 19 = 4 - 19

Simplify: x/2 = 15

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Simplify: x = -30

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3 years ago
Given a table of values of a quadratic function, which of the following do you absolutely need in order to find its equation? *
nadya68 [22]

Answer:

The general form of a quadratic function is --> y = ax2 + bx + c

Since (0, -2) exists for the function, we can plug in those values:

-2 = a(0)2 + b(0) + c

-2 = 0 + 0 + c

-2 = c

So now our function so far is --> y = ax2 + bx - 2

We have two pairs of coordinates left: (-1, -8) and (3, -8).

First, plug in the first pair and simplify as much as you can:

-8 = a(-1)2 + b(-1) - 2

-8 = a - b - 2 ( add 2 to both sides )

-6 = a - b (stop here because we can't go further)

Second, plug in the second pair and simplify as much as you can:

-8 = a(3)2 + b(3) - 2

-8 = 9a + 3b - 2 ( add 2 to both sides )

-6 = 9a + 3b (stop here because we can't go further)

Now we have these two equations left:

a - b = -6

9a + 3b = -6

Now we solve for a and b using systems of equations, using one of three ways:

substitution

elimination

graphing (not my favorite, but it is doable)

Using substitution:

a - b = -6 can be rewritten as a = b - 6

plug into the second equation and solve for b

9(b - 6) + 3b = -6 (distribute the 9)

9b - 54 + 3b = -6 (combine all of the b's)

12b - 54 = -6 (add 54 to both sides)

12b = 48 (divide by 12 on both sides to isolate b)

b = 4

plug b into one of the original two equations

a - 4 = -6 (add 4 to both sides)

a = -2

The quadratic equation for this table is y = -2x2 + 4b - 2

6 0
2 years ago
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