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myrzilka [38]
3 years ago
9

Three years ago, the annual tuition at a university was $2,000. The following year, the tuition was $2,200, and last year, the t

uition was $2,420. If the tuition has continued to grow in the same manner, what is the tuition this year? What do you expect it to be the next year?
Mathematics
2 answers:
Andre45 [30]3 years ago
8 0

The answers would be 2662 for this year, and 2982.2 for the year after. I just checked it and I hope it will help!

blondinia [14]3 years ago
7 0
It grows by 10% each year. multiply the number by 0.1, then add. so 0.1×2420 is 242. add 242+2420=2662.

short answer:
this years tuition is $2662.
next years tuition is $2928.
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Verdich [7]

Answer:

C) Impossible

Step-by-step explanation:

Since there are no blue cards, the probability that you'd draw one is 0/12, which means that there is no chance you'll draw one.

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3 years ago
The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p
Juliette [100K]

Check the picture below.


based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,


\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)


\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}


now, we can plug those values on A = (1/2)bh,


\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5

7 0
3 years ago
Wilhelmina wrote a check for $72 to pay her monthly Internet bill, but when
lesantik [10]

Answer:

her bank statement will show that she has $144 less than her checkbook balance

Step-by-step explanation:

let the amount of money in the bank before writing the check be x

after writing the check for $72, because she accidentally recorded this as a credit, here checkbook will reflect a balance of :$(x + 72)

However, the bank correctly records the debit of the $72, resulting  a balance of: $(x-72)

Hence compared to her checkbook,  the bank records will show an amount difference of :

(x-72) - (x + 72)

= x - 72 -x -72

= -144

i.e her bank statement will show that she has $144 less than her checkbook balance

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Y=3x+4<br><br> Fill in the missing values for the table.
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3(-1.5) + 4 = -0.5
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