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stellarik [79]
3 years ago
15

Can someone solve this? i have a photo.

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0

Answer: (25,9)

Step-by-step explanation:

In order to write an equivalent equation for the first equation, you can multiply both sides by 15:

(15)(\frac{x}{5}+\frac{y}{3})=(8)(15)\\\\3x+5y=120

Then, you get this system of equations:

\left \{ {{3x+5y=120} \atop {x-2y=7}} \right.

Now, you can apply the Elimination Method to solve the system of equations:

1. Multiply the second equation byb -3.

2. Add the equations.

3. Solve for "y".

Then:

\left \{ {{3x+5y=120} \atop {-3x+6y=-21}} \right.\\.....................\\11y=99\\\\y=9

4. Substitute the value of "y" into any original equation and solve for "x" in order to find its value:

x-2(9)=7\\\\x=7+18\\\\x=25

5. The solution is:

(25,9)

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Raj’s farmhouse is 1245km away from hiswarehouse. Daily he drivesa certain distance and then his friend Rohantakes aturn to driv
mariarad [96]

Answer:

Step-by-step explanation:

Subtract the distance driven by Rohan from the total distance

Distance driven by Raj = 1245 - 412

                                     = 833 km

8 0
3 years ago
FILL IN THE BLANK!!!
Arisa [49]
''36'' atp molecules would be the answer
7 0
4 years ago
Which expression is the simplest form of -(4x + y)n + 2(x - 3y)
Marina86 [1]

Answer:

\boxed{\bold{-4nx-ny+2x-6y}}

Explanation:

Rewrite:

= \bold{-n\left(4x+y\right)+2\left(x-3y\right)}

Expand \bold{-n\left(4x+y\right): \ -4nx-ny}

= \bold{-4nx-ny+2\left(x-3y\right)}

Expand \bold{2\left(x-3y\right): \ 2x-6y}

= \bold{-4nx-ny+2x-6y}

Mordancy.

4 0
4 years ago
Here's another, Thanks. (3/5)
Pachacha [2.7K]

You are correct. The scale factor is 1/5 = 0.2

Nice work.

7 0
3 years ago
In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th
zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

\frac{x}{y}=\frac{1}{3}

y=3x ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the  number of additional red circles

\frac{x+n}{y}=\frac{3}{1} ----> equation B

substitute equation A in equation B

\frac{x+n}{3x}=\frac{3}{1}

solve for n

x+n=9x\\n=9x-x\\n=8x

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

5 0
3 years ago
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