Answer:
First Image: Option D
Second Image: Option D
Third Image: Option C
Fourth Image: Option B
Fifth Image: Option B
Step-by-step explanation:
<u>First Image:</u>
- Supplementary angles is two angles whose sum is 180 degrees (straight line)
- 180 - 47 = 133°
- ? is an obtuse angle is any angle greater than 90° which checks the answer
<u>Second Image:</u>
- A triangle angles adds up to 180°
- Two angles are already given
- 72 + 45 + ? = 180° → 117 + ? = 180° → ? = 63°
- ? is an acute angle is an angle that measures between 90° and 0°
<u>Third Image:</u>
- Supplementary angles is two angles whose sum is 180 degrees (straight line)
- 180 - 110 = 70°
- ? is an acute angle is an angle that measures between 90° and 0°
<u>Fourth Image:</u>
- Supplementary angles is two angles whose sum is 180 degrees (straight line)
- 180 - 120 = 60°
- we are shown a right angle which = 90°
- A triangle adds up to 180°
- 180 - 90 - 60 = 30
- ? = 30°
- ? is an acute angle is an angle that measures between 90° and 0°
<u>Fifth Image:</u>
- Supplementary angles is two angles whose sum is 180 degrees (straight line)
- 180 - 85 = 95°
- ? is an obtuse angle is any angle greater than 90° which checks the answer
Learn more about Triangles here: brainly.com/question/4186813
Answer: 19 macaroons
Step-by-step explanation:
Let's create an equation to represent this situation. Let x represent the number of macaroons that Em made.
33=x+x+5
33=2x+5
33-5=2x+5-5
28=2x
28/2=2x/2
14=x
This means that Em made 14 macaroons.
14+5=19
Therefore, Jim baked 19 macaroons.
The commutative property of multiplication.
So... let's say the smaller regular octagon has sides of "x" long, then the larger octagon will have sides of 5x.
![\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &Sides&Area&Volume\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array} \\\\ -----------------------------\\\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bratio%20relations%7D%0A%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccllll%7D%0A%26Sides%26Area%26Volume%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%26%5Ccfrac%7Bs%7D%7Bs%7D%26%5Ccfrac%7Bs%5E2%7D%7Bs%5E2%7D%26%5Ccfrac%7Bs%5E3%7D%7Bs%5E3%7D%0A%5Cend%7Barray%7D%20%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%5Cqquad%20%5Ccfrac%7Bs%7D%7Bs%7D%3D%5Ccfrac%7B%5Csqrt%7Bs%5E2%7D%7D%7B%5Csqrt%7Bs%5E2%7D%7D%3D%5Ccfrac%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)
