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just olya [345]
3 years ago
7

PLEASE HELP SUPER EASY MATH PROBLEM WILL MARK BRAINLIEST

Mathematics
2 answers:
topjm [15]3 years ago
8 0

Answer:

m∠5 = 67

m∠7 = 67

Step-by-step explanation:

m∠4 and m∠5 add up to 180 because they are same side interior angles.

180 - 113 = m∠5

m∠5 = 67

m∠5 = m∠7 because they are vertically opposite angles

hence, m∠7 = 67 degrees  

strojnjashka [21]3 years ago
4 0

Answer:

angle 5: 67 degrees. Angle 7: 67 degrees. (make sure to add the degrees logo)

Step-by-step explanation:

basically, angle 4 is 113 degrees. 180 degrees minus 113 is 67, which is how much angles 1 and 3 are. angles one and three are also equivalent to 5 and 7, which means they are also 67 degrees

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Answer:

\dfrac{14}{29}

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

P(A \cap E) will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

P(B \cap E) will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

P(E \cap A) = P(A) \times P(E/A)

P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%

P(E \cap B) = P(B) \times P(E/B)

P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%

P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

P(B/E) = \dfrac{P(E \cap B)}{P(E)}

\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}

So, the required probability is \dfrac{14}{29}.

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