All categories

3 years ago

PLEASE HELP SUPER EASY MATH PROBLEM WILL MARK BRAINLIEST

Mathematics

2 answers:

topjm [15]3 years ago

8 0

Answer:

m∠5 = 67

m∠7 = 67

Step-by-step explanation:

m∠4 and m∠5 add up to 180 because they are same side interior angles.

180 - 113 = m∠5

m∠5 = 67

m∠5 = m∠7 because they are vertically opposite angles

hence, m∠7 = 67 degrees

strojnjashka [21]3 years ago

4 0

Answer:

angle 5: 67 degrees. Angle 7: 67 degrees. (make sure to add the degrees logo)

Step-by-step explanation:

basically, angle 4 is 113 degrees. 180 degrees minus 113 is 67, which is how much angles 1 and 3 are. angles one and three are also equivalent to 5 and 7, which means they are also 67 degrees

You might be interested in

Which statement correctly compares the function shown on this graph with

Alex

Answer:

Y=4X+2

Y=4X

4X/2

4*2+2=Y

Y=2

Step-by-step explanation:

3 0

3 years ago

How can area models be used to solve multiplication problems?

tester [92]

Area is basically multiplication. You multiply the length by the width

3 0

3 years ago

Workers are loading boxes onto a truck. So far, they have loaded 48 boxes onto the truck

Talja [164]

Answer:

1,200 total on truck

Step-by-step explanation:

48=4% loaded on a truck and they have 96% left to load

So set up a proportion and it should look like this

48 over x = 4 over 100

48/x=4/100

Do cross multiplication 100×48= 4,800÷ 4 = 1,200 total on truck

=1,200 total on truck

Hope this helps, have a nice day! :D

5 0

3 years ago

Value of 5 to the power of 4 over 5 to the power of 6

Yuki888 [10]

Answer:

5 to the power of 4 = 625

5 to the power of 6 = 15625

Step-by-step explanation:

5 x 5 x 5 x 5 x 5 = 625

5 x 5 x 5 x 5 x 5 x 5 = 15625

4 0

2 years ago

Int(1 \(1 + {e}^{x} )

Andreyy89

Answer:

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx}= x - \ln(1 + e^{x}) + C\end{aligned}$ .

Step-by-step explanation:

The first derivative of the denominator $1 + e^{x}$ is $e^{x}$ . Rewrite the fraction to obtain that expression on the numerator.

$\begin{aligned}\frac{1}{1 + e^{x}} &= \frac{1 + e^{x}}{1 + e^{x}} - \frac{e^{x}}{1+e^{x}}\\&=1-\frac{e^{x}}{1+e^{x}}\end{aligned}$ .

In other words,

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\end{aligned}$ .

Apply $u$ -substitution on the integral $\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx}$ :

Let $u = 1 + e^{x}$ . $u > 1$ .

$du = e^{x}\cdot dx$ .

$\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx} = \int{\frac{du}{u}} = \ln{|u|} = \ln{u} +C = \ln{(1+e^{x})}+C$ .

Therefore

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\\ & = x - \ln{(1 + e^{x})}+C\end{aligned}$ .

7 0

3 years ago