Drifting through the wind, wanting to start again PSHWIWIEI
We have been given that ∠Q is an acute angle such that 
. We are asked to find the measure of angle Q to nearest tenth of a degree.
We will use arctan to solve for measure of angle Q as:
Now we will use calculator to solve for Q as:
Upon rounding to nearest tenth of degree, we will get:
Therefore, measure of angle Q is approximately 2.3 degrees.
Answer:
The first one
Step-by-step explanation:
g(x) = ax² + bx + c
Point (0,0):
0 = a.0² + b.0 + c
c = 0
Point (2,1):
1 = a.2² + b.2 + c
4a + 2b + c = 1
But c = 0. Then:
4a + 2b = 1
Another point: (- 2, 1):
1 = a.(- 2)² + b.(- 2) + c
4a - 2b = 1
{4a + 2b = 1
{4a - 2b = 1
4a + 2b = 4a - 2b
4a - 4a = - 2b - 2b
- 4b = 0
b = 0
4a + 2b = 1
4a + 2.0 = 1
4a = 1
a = 1/4
The formula is:
g(x) = (1/4)x²
I hope I've helped you.
Answer:
x=21° and ∠KMH=96°
Step-by-step explanation:
From the given information that a bike path crosses a road and the given figure, we get
∠GMH=∠KMI=84°(Vertically opposite angles)
⇒4x=84°
⇒x=21°
therefore, the value of ∠GMH=4x=4(21)=84°
Now, ∠KMH+∠KMI=180°( Linear pair)
⇒∠KMH+84°=180°
⇒∠KMH=180-84
⇒∠KMH=96°
Thus, the value of ∠KMH is 96°
