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3 years ago

Mrs. Walters buys 5 and 1/4 pounds of strawberries for $8.40. What is the unit cost of the strawberries?

Mathematics

2 answers:

Elis [28]3 years ago

6 0

Answer:

1.6pounds per unit

Step-by-step explanation:

Mrs walters buys 5 and 1/4 pounds of strawberry's for 8.40 as our whole price

We are trying to find out how much each of the strawberrys will cost so we need to

Divide the whole sale price for the amount bought. We get

1.6 as our unit price

To check this we can multiply by 5 1/4 wich gives us

8.4 or 8.40 So our anwer is

1.6 pounds

Arisa [49]3 years ago

3 0

8.40/5.25=1.6 hope this helps

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2 years ago

B: Alex is 12 years older than George.

UkoKoshka [18]

Answer:

The ratio of George age to Carl's age is 1:12.

Step-by-step explanation:

Let the age of George be 'g'.

Let the age of Alex be 'a'.

Also Let the age of Carl be 'c'.

Given:

The sum of their ages is 68.

So equation can be framed as;

$g+a+c=68 \ \ \ \ equation 1$

Also Given:

Alex is 12 years older than George.

So equation can be framed as;

$a =g+12 \ \ \ \ equation \ 2$

Now Given:

Carl is three times older than Alex.

$c=3a$

But $a =g+12$

So we get;

$c = 3(g+12) \\\\c= 3g+36 \ \ \ \ equation \ 3$

Now Substituting equation 2 and equation 3 in equation 1 we get;

$g+a+c=68\\\\g+g+12+3g+36=68\\\\5g+48=68$

Subtracting both side by 48 using subtraction property of equality we get;

$5g+48-48=68-48\\\\5g=20$

Now Dividing both side by 5 using Division property of equality we get;

$\frac{5g}{5}=\frac{20}{5}\\\\g =4$

Hence George age $g = 4 \ years$

Now Alex age $a=g+12 = 4+12 =16\ years$

Also Carl's age $c=3g+36=3\times 4+36 =12+36 =48\ years$

Now we need to find the ratio of George age to Carl's age.

$\frac{g}{c}=\frac{4}{48} = \frac{1}{12}$

Hence the ratio of George age to Carl's age is 1:12.

3 0

3 years ago