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Ksenya-84 [330]
3 years ago
9

The path followed by a roller coaster as it climbs up and descends down from a peak can be modeled by a quadratic function, wher

e h(x) is the height, in feet, and x is the horizontal distance, also in feet. The path begins and ends at the same height, covers a total horizontal distance of 100 feet, and reaches a maximum height of 250 feet. Which of the functions could be used to model this situation?
Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

y = -0.1x^2 + 250 ft

Step-by-step explanation:

Because this quadratic equation would have the curve-down form of:

y = -ax^2 + b

where a and b are positive coefficient.

If we let the peak (250 ft) of the curve be at x = 0. Then

y = -a0^2 + b = 250

b = 250

Also at the begins and ends, thats where y = 0, the 2 points are separated by 100 ft. So let the begin at -50 ft and the end at 50ft. We have

-a(\pm 50)^2 + 250 = 0

-a2500 = -250

a = 250/2500 = 0.1

Therefore, the model quadratic equation of our path would be

y = -0.1x^2 + 250 ft

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(6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)

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Let Event A be the event that the player made both throws

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