Kristina invests $5,000 at 15% simple interest for 2 years.How much interest did Kristina earn over the 2 years?

Select the correct location on the table.

Bas_tet [7]

Answer:

left one on 3rd row

Step-by-step explanation:

using the rules of exponents/ radicals

$a^{-m}$ = $\frac{1}{a^{m} }$

$a^{\frac{m}{n} }$ = $\sqrt[n]{a^{m} }$

given

$12^{-\frac{4}{7} }$

= $\frac{1}{12^{\frac{4}{7} } }$

= $\frac{1}{\sqrt[7]{12^{4} } }$

6 0

2 years ago

Last year, a janitorial supervisor had a gross income of $34,100, of which he contributed 8% to his 401(k) plan. If he got paid

rodikova [14]

There was a gross income of 34,100....8% goes to 401K plan..
8% of 34,100 = 0.08(34,100) = 2728

he gets paid bimonthly...so he gets paid twice a month...and being that there is 12 months in a year, he gets paid (12 * 2) = 24 times

2728/24 = 113.666 rounds to 113.67 each paycheck <==

4 0

4 years ago

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Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.

skad [1K]

Answer:

$\displaystyle A=\frac{x-2}{x+3}$

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

$\displaystyle S=\frac{x-3}{x+2}$

Let's suppose one of the expressions is:

$\displaystyle A=\frac{x-2}{x+3}$

Now we subtract S minus A to find the other expression B:

$\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}$

Multiply the first fraction by x+3 and the second by x+2;

$\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}$

Operating:

$\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}$

Subtracting both fractions with like denominators:

$\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}$

Simplifying:

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

Thus the two expressions are:

$\displaystyle A=\frac{x-2}{x+3}$

And

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

8 0

3 years ago

Some of Mrs. Turay’s eighth graders took the PSAT test. Score totals of ten of her students are below. Calculate the mean and th

den301095 [7]

Answer:

(a) Mean=74

(b) Median=70

(c) The best measure of center= Median.

Step-by-step explanation:

We have been given a data set of PSAT scores of Mrs. Turay's eight graders. We are asked to find mean and median of the given data set.

(a) Let us find mean of data set by dividing the sum of given scores by the number of students.

$\text{Mean}=\frac{60+62+67+69+70+70+71+75+76+120}{10}$

$\text{Mean}=\frac{740}{10}=74$

Therefore, the mean test score will be 74.

(b) Now let us find median of our given data set. We have been given that number of students is 10, therefore, our median will be the average of 5th and 6th term.

60, 62, 67, 69, 70, 70, 71, 75, 76, 120.

We can see that 5th term is 70 and 6th term is 70 as well.

$\text{Median}=\frac{70+70}{2}$

$\text{Median}=\frac{140}{2}$

$\text{Median}=70$

Therefore, the median test scores will be 70.

(c) We can see that our data set has an outlier score as 120, which has increased the mean. Mean score is greater than median score. Since median is not affected by extreme value outliers, therefore, median will be the best measure of center for given test scores.

3 0

4 years ago

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Find the LCM of 4 and 9 A. 9 B. 35 C. 72 D. none of the above

Vitek1552 [10]

B is the answer becuase it’s 35 and that should be correct

7 0

3 years ago

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