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3 years ago

Simplify 7(n+2) A 7n-14 B -7n+14 C n+9 D 7n+14

Mathematics

1 answer:

zzz [600]3 years ago

5 0

The answer is D, 7n + 14.

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<img src="https://tex.z-dn.net/?f=%5Bx%5E%7B2%2F5%7D%20%5D%5Bx%5E%7B1%2F5%7D%20%5D" id="TexFormula1" title="[x^{2/5} ][x^{1/5} ]

LUCKY_DIMON [66]

Answer:

$[x^{2/5} ][x^{1/5} ] \\ \\ = {x}^{ \frac{2}{5} + \frac{1}{5} } \\ \\ = {x}^{ \frac{2 + 1}{5} } \\ \\ = {x}^{ \frac{3}{5} } \\$

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3 years ago

Problem: 2x+3 (x-4)=x-20

monitta

Let's solve your equation step-by-step.2x+3(x−4)=x−20Step 1: Simplify both sides of the equation.2x+3(x−4)=x−20Simplify: (Show steps)5x−12=x−20Step 2: Subtract x from both sides.5x−12−x=x−20−x4x−12=−20Step 3: Add 12 to both sides.4x−12+12=−20+124x=−8Step 4: Divide both sides by 4.4x/4=−8/4x=−2Answer: x=−2

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3 years ago

A city traffic light cycles through green, yellow, and red in 60 seconds. It is yellow for 3 seconds. Which term best describes

Paha777 [63]

Answer:

Step-by-step explanation:

5 0

3 years ago

11. Little Sally Walker has a choice between going to an in-state college where she would pay

nalin [4]

Answer:

Step-by-step explanation:

Lets calculate first for in state college

yearly tuition fees = $3,500

monthly living expense = $700

one year has 12 months so yearly living expense =$700 * 12 = $8,400

Yearly expense of the in state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400) = $3,500 + $8,400 = $11,900

____________________________________________________

Lets calculate first for out of state college

yearly tuition fees = $6,000

monthly living expense = $400

one year has 12 months so yearly living expense =$400 * 12 = $4,800

Yearly expense of the out of state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400) = $6,000 + $4,800 = $10,800

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3 0

3 years ago

The equation line l is given by the equation y= 7/4x+3. line m goes through the point ( –1,4) and is perpendicular to line l whi

mr_godi [17]

We determine line m as follows:

*First, by theorem we have the following:

$m_1=-\frac{1}{m_2}$

Here m1 & m2 are the slopes of two perpendicular lines. For all lines that are perpendicular that is true, so we calculate the slope of line m using the slope of the function given [Which has a slope of 7/4]:

$m_1=-\frac{1}{\frac{7}{4}}\Rightarrow m_1=-\frac{4}{7}$

So, the slope of line m is -4/7. Now, using this slope and the point (-1, 4) we replace in the following expression:

$y-y_1=m_1(x-x_1)$

Here x1, y1 & m1 are the x-component of the point, the y-component of the point, and the slope of the line respectively, so we replace and solve for y:

$y-4=-\frac{4}{7}(x-(-1))\Rightarrow y-4=-\frac{4}{7}x-\frac{4}{7}$ $\Rightarrow y=-\frac{4}{7}x+\frac{24}{7}$

And that last function of y is the line m.

8 0

1 year ago