Pls find the surface area for me

A florist has 492 flowers. How many full bouquets of 12 flowers can he make?

Talja [164]

492 divided by 41= 41. He can make 41 full bouquets.

6 0

3 years ago

The expression P(z > –1.53) represents the area under the standard normal curve above a given value of z. Find P(z > –1.53

Damm [24]

We can only look up the value in the normal distribution table if the probability of z is LESS than a certain value AND the value is positive.
If the probability of z is MORE than the value, then you need to do 1 minus the probability.
I.e. 1 - 0.93699
[0.93699 is found in the normal distribution table, searching for 1.53]
However, since the value (-1.53) is also negative, you need to do 1 minus AGAIN.
I.e. 1 - 0.93699

Since you have to do both, the answer should be obtained as follows:
1 - (1 - 0.93699) = 0.93699

Sorry for the terrible explanation :/
And apologies if anything is incorrect. Hope this helped though!

6 0

3 years ago

Medal will be awarded:. When constructing an inscribed polygon with a compass and straightedge, how should you start the constru

Ymorist [56]

The draw an inscribed polygon inside the circle, the very thing to do is to draw the circle. Thus, the answer is the fourth choice, "Place a point on your paper and then use a compass to construct a circle". After which, we can locate the vertices of the polygon in the circumference of the circle and connect them to make the polygon.

6 0

4 years ago

I need help with this ASAP!!

stepladder [879]

The answer to this would be 45

5 0

3 years ago

Read 2 more answers

A study by Consumer Reports showed that 64% of supermarket shoppers believe supermarket brands to be as good as national name br

natima [27]

Answer:

Step-by-step explanation:

Given that:

A study is conducted and the study by Consumer Reports showed that 64% of supermarket shoppers believe supermarket brands to be as good as national name brands.

a)

Thus; we formulate the null and the alternative hypotheses as follows:

The proportion is ; $\frac{64}{100}$ = 0.64

Null hypothesis: ${H_0}:p = 0.64$

The Null hypothesis states that there is no evidence that “the percentage of supermarket shoppers believes that the supermarket ketchup is good as the national brand ketchup differ form 64%”.

Alternative hypothesis: ${H_a}:p \ne 0.64H$

The Alternative hypothesis states that there is evidence that “the percentage of supermarket shoppers believes that the supermarket ketchup is good as the national brand ketchup differ form 64%”.

b)

The proportion of the population = 0.64

The sample size n = 100

The number of shoppers = 52 stating that the supermarket brand was as good as the national brand

The sample proportion $\hat p = \frac{52}{100}$

$\hat p = 0.52$

The z - value is calculated by the formula:

$z = \dfrac{\hat p-p}{\frac{\sqrt{ p(1-p)}}{100 }}$

$z = \dfrac{0.52-0.64}{\frac{\sqrt{ 0.64(1-0.64)}}{100 }}$

$z = \dfrac{-0.12}{0.048 }}$

z = -2.50

Since z = -2.50

the p-value = 2P(Z ≤ -2.50)

p-value = 2 × 0.0062

The p-value = 0.0124

c)

At significance level, ∝ = 0.05 ; The p-value = 0.0124

According to the rejection rule, if p-value is less than 0.05 then we will reject null hypothesis at ∝ = 0.05

Hence, the p-value =0.0124 < ∝ (=0.05)

According to the reject rule; reject null hypothesis.

Conclusion: There is no evidence at all that the percentage of supermarket shoppers believes that the supermarket ketchup is good as the national brand ketchup differ form 64%.

d) we know that the significance level of ∝ = 0.05

The value ${z__{0.05}}$ is obtained as:

$P\left( {\left| Z \right| \le z} \right) = 0.05$

Now; to determine Z ; we locate the probability value of 0.05 form the table of standard normal distribution. Then we proceed to the left until the first column is reached and the value is 1.90. Also , we move upward until we reach the top and the value is 0.06. Now; the intersection of the row and column results the area to the left of z

This implies that : $P(Z \leq -1.96)=0.05$

The critical value for left tail is -1.96 and the critical value for right tail is 1.96.

Conclusion:

The critical value is -1.96 and the value of test statistic is - 2.50. Here, we can see that the value of test statistic is lesser than the critical value. Hence, we can be concluded that there is evidence that reject the null hypothesis.

Therefore, Yes, the national brand ketchup manufacturer is pleased with the conclusion.

5 0

3 years ago