Step-by-step explanation: In algebra, we use the word <em>slope</em> to describe how steep a line is and slope can be found using the ratio <em>rise/run </em>between any two points that are on that line.
The ratio <em>rise/run</em> is the equal to the rate of change
or the <em>change in y/change in x</em>.
In algebra, the rate of change or the <em>change in y/change in x</em> or
the <em>rise/run</em> is also called the slope of a line.
Answer:
y = 2x + 6 and 2y-4x=12 are the same line, so have infinitely many solutions.
Step-by-step explanation:
2y - 4x = 12
This is the same as y = 2x + 6
Answer:
The equation for rational function for given asymptotes is
f(x)=(-4x^2-6)/{(x-3)(x+3)}
Step-by-step explanation:
Given:
vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at
y=-4 i.e parallel to x axis.
To find:
equation of a rational function i.e function in form p/q
Solution;
the equation should be in form of p/q
Numerator :denominator.
Consider f(x)=g(x)/h(x)
as vertical asymptote are x=-3 and x=3
denominator becomes, (x-3) and (x+3)
for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'
when g(x) will be degree '2' with -4 as coefficient and dont have any real.
zero.
By horizontal asymptote will be (-4x^2 -6)
The rational function is given by
f(x)=g(x)/h(x)
={(-4x^2-6)/(x-3)(x+3)}.
Answer:
B. 43°
Step-by-step explanation:
Internal angles of the triangle are:
So It is a right triangle and the missing angle is:
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
