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rosijanka [135]
2 years ago
8

Will get brainily sign if you get it correct with explanation!!!!!

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
4 0

Answer:

<u><em>$4.50 or $4.5</em></u>

Step-by-step explanation:

<em><u>well, this is easy</u></em>

<em><u>30% equals to 0.30 right.</u></em>

<em><u>we can't divide because if we do then the answer would be 50$ and that's way more money than Jill has.</u></em>

<em><u>so your wondering. What do we do?</u></em>

<em><u>Well, what's 30% of 15?</u></em>

<em><u>It's 4.5</u></em>

<em><u>4 dollars and 5 cents that U will have with Jill.</u></em>

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Please help meee! I will give brainleiest!
Serjik [45]

Answer:

B) 3.0 ml

Step-by-step explanation:

5 0
2 years ago
ANSWER FAST <br> NO LINKS<br> 23=x-13<br><br> 9+x=14<br><br> 12=x+8
Anna35 [415]

Answer:

23=x-13, x=36

9+x=14, x=5

12=x+8, x=4

Step-by-step explanation:

23=x-13. You want to isolate x so you have to add 13 to both sides. x=23+13, x=36

9+x=14. You want to isolate x so you have to subtract 9 from both sides. x=14-9, x=5.

12=x+8. You want to isolate x so you have to subtract 8 from both sides. x=4.

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3 0
3 years ago
The product of a number and -7 is 63
Oduvanchick [21]
-7n=63
n=-9 is your final answer. Hope it help!
3 0
3 years ago
The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72
Brut [27]

Answer:

The maximum number of songs that the symphonic choir can record is 14

Step-by-step explanation:

Let

x ----> the number of songs of the symphonic choir

we know that

The number of songs of the jazz choir multiplied by its average time per song plus the the number of songs of the symphonic choir multiplied by its average time per song, must be less than or equal to 72 minutes

so

The inequality that represent this situation is

3(7)+3.5(x)\leq 72

solve for x

21+3.5x\leq 72

subtract 21 both sides

3.5x\leq 51

divide by 3.6 both sides

x\leq 14.6\ songs

therefore

The maximum number of songs that the symphonic choir can record is 14

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2 years ago
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