Answer:
The Least Common Denominator of 3/4, 4/5 and 2/3
Would be,
4 × 5 × 3 = 60
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>60</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>L.C.D</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>3</u></em><em><u>/</u></em><em><u>4</u></em><em><u>,</u></em><em><u> </u></em><em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u>/</u></em><em><u>3</u></em>
The answer is b just take the decimal off and subtract
Total number of fields of vegetables = 62
Thus,
The amount of fields that is cabbage =
<span>−4(3−1)+2
=</span><span>−4(2)+2
= -8 + 2
= -6</span>
Answer:
f(x)= -(x+1)^2 -2
Step-by-step explanation:
f(x)=(x-h)^2 +k; (h,k)
Then you would substitute the x and y of the coordinate and solve.
-6= -(1+1)^2 -2
-6= -(4) -2
-6 = -6
