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allochka39001 [22]

3 years ago

14

One way to solve the system is to _____________ a variable.

2 answers:

Ivahew [28]3 years ago

8 0

One way to solve the system is to <u>substitute</u> a variable.

<u>Explanation:</u>

One approach to solve an equation is by substitution of one variable. Right now, a condition for one factor, at that point substitute that arrangement in the other condition, and explain. All value(s) of the variable(s) that fulfills a condition, disparity, arrangement of conditions, or arrangement of imbalances.

The technique for tackling "by substitution" works by settling one of the conditions (you pick which one) for one of the factors (you pick which one), and afterward stopping this go into the other condition, "subbing" for the picked variable and fathoming for the other. At that point you back-explain for the principal variable.

Norma-Jean [14]3 years ago

7 0

Answer:

eliminate

Step-by-step explanation:

If you're using USA Test Prep it's eliminate.

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A pancake recpe calls for 1/2 cup of milk and 3/4 Of a cup of flour.If you multiply the recipe by 5 how much flour will you need

Andre45 [30]

In total 2/4 + 3/4 = 8/4 x 5 = 25/20 total
2/4 x 5 = 10/20 milk
3/4 x 5 = 15/20 flour

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3 years ago

Write an equation for the situation There are 8 nickels and d dimes in your pocket. The nickels and dimes have a total value of

Contact [7]

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5 0

3 years ago

Read 2 more answers

Use the grouping method to factor x^3+x^2+3x+3

maks197457 [2]

Answer:

(x^2 + 3)(x + 1).

Step-by-step explanation:

x^3 + x^2 + 3x + 3

= x^2(x + 1) + 3(x + 1)

= (x^2 + 3)(x + 1).

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3 years ago

Round 6.94729776259 to 5 decimal places.

blagie [28]

Answer

6.9473

Step-by-step explanation:

7 0

3 years ago

8x^-9+(-3x^-3y-2)(5/x^6y-2)

DaniilM [7]

$8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})$

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

$\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})$

now we can simplify the multiplied terms

$\frac{8}{x^9}+(\frac{-15}{x^9})$

Now that we have common bases, we can add the 2 fractions together to get

$\frac{-7}{x^9}$

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3 years ago