The last one is the only one that will work.
For the first one the y intercept is when x = 0. The point would be 0,4
The second one gives a point of (4,0)
The third one is nonsense. (4,4) is not on this line.
Answer:
y = (7/2)x -20
Step-by-step explanation:
The given line is in slope-intercept form, so you can read its slope from the equation.
y = mx + b . . . . . m is the slope; b is the y-intercept
y = -(2/7)x + 9 . . . . . . has slope -2/7
The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...
m = -1/(-2/7) = 7/2
We can use this and the given point to write the equation in point-slope form.
y = m(x -h) +k . . . . . . line with slope m through point (h, k)
We have m = 7/2, (h, k) = (4, -6) so the equation is ...
y = (7/2)(x -4) -6
y = (7/2)x -20
The equation is already is slope intercept form where you can easily point out the gradient, or the slope, and the y intercept.
y=mx+b where m is the gradient, and b is the y intercept.
Since there is no m, the gradient is 1.
The y intercept had x=0 and y=b
b in this case is 6
the y intercept= (0,6)
Answer:
nice
Step-by-step explanation: