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2 years ago

Find the measure of angle2 A. 90 B. 50 C. 60 D. 30

Mathematics

1 answer:

galina1969 [7]2 years ago

6 0

I think it is C. 60.
You can eliminate A because it is not a right angle, and D because the angle is bigger than the given angle. So it is between 50 and 60, and I hope this is right and the picture makes sense

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X and Y are loss random variables, with X discrete and Y continuous. The joint density function of X and Y is f(x, y) = [(x+1)e-

STALIN [3.7K]

Answer:

The probability that the total loss, X + Y is less than 2 is P=0.235

Step-by-step explanation:

We know the joint density function:

$f(x,y)=\frac{(x+1)e^{-y/2}}{12}$

To find the probability that (X+Y)<2, we can divide this in two steps.

- When X=0, Y should be less than 2. This is P(X=0,Y<2).

- When X=1, Y should be less than 1. This is P(X=1, Y<1).

We can calculate P(X=0,Y<2) as:

$P(X=0,Y$

We can calculate P(X=1,Y<1) as:

$P(X=1,Y$

Then

$P(X+Y$

3 0

2 years ago

Solve the inequality. Graph the solution +5<2 The solution is a 6

BartSMP [9]

Answer:

x<-3

The graph in the attached figure

Step-by-step explanation:

The correct question is

Solve the inequality. Graph the solution.

x+5<2

we have

$x+5$

Solve for x

Subtract 5 both sides

$x$

The solution is the interval (-∞,-3)

All real numbers less than -3

In a number line, the solution is the shaded area at left of x=-3 (open circle)

The number x=-3 is not included in the solution

The graph in the attached figure

7 0

2 years ago

The usher at a wedding asked each of the 808080 guests whether they were a friend of the bride or of the groom. Here are the res

malfutka [58]

Complete Question

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests, n(S)=80

Let the Event (a friend of the bride) =B

Let the Event (a friend of the groom) =G

n(B) =59

n(G)=50

$n(B \cap G)=30$