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kotykmax [81]
3 years ago
13

Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

Part A What is the x component v⃗ x of v⃗ ?
Physics
1 answer:
kramer3 years ago
5 0

Answer:

  v_x = -6\ m/s

Explanation:

initial velocity

magnitude of velocity, v = 12 m/s

angle made of velocity with negative x-axis,θ = 60°

We need to calculate x- component of v

  v_x = v cos \theta

velocity is in negative x-direction, v = -12 m/s

now,

  v_x = -12\times cos 60^0

  v_x = -12\times 0.5

  v_x = -6\ m/s

Hence, the velocity x-component is equal to -6 m/s.

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