Question

Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis. Part A What is the x component v⃗ x of v⃗ ?

Answer 1

Answer:

  $v_x = -6\ m/s$

Explanation:

initial velocity

magnitude of velocity, v = 12 m/s

angle made of velocity with negative x-axis,θ = 60°

We need to calculate x- component of v

  $v_x = v cos \theta$

velocity is in negative x-direction, v = -12 m/s

now,

  $v_x = -12\times cos 60^0$

  $v_x = -12\times 0.5$

  $v_x = -6\ m/s$

Hence, the velocity x-component is equal to -6 m/s.