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Mariana [72]
4 years ago
12

The view that time is a scarce resource that must be rationed and controlled through the use of schedules and appointments, and

through aiming to do only thing at a time is:
Physics
1 answer:
Diano4ka-milaya [45]4 years ago
6 0

Answer:

Monochronic.

Explanation:

This view is called as Monochronic.

The dictionary definition of Mono-chronic is that  Monochronic people just like to do one thing at a time. They respect a certain uniformity and sense of being a suitable place and time for different activities. They don't esteem interruptions. It has been generally observe that their focus and productivity remains higher than the polychronic.( Those we are comfortable with performing multiple task at a time)

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The answer to this question is a the estimate the speed of light
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Why does paper stand up when a van de graaf generator is on?
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because follicles are getting charged to the same potential

Explanation:

7 0
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2. A truck speeds up from a velocity of 6 m/s to 14 m/s in 4 seconds. What is the trucks acceleration? SHOW YOUR WORK
zavuch27 [327]

#2

As it is given here

initial speed is

v_i = 6 m/s

After 4 seconds the final speed is

v_f = 14 m/s

so here we can use the formula of acceleration using kinematics

a = \frac{v_f - v_i}{t}

a = \frac{14 - 6}{4}

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so here it will accelerate at 2 m/s^2 rate.

#3

As it is given here

initial it starts from rest

v_i = 0 m/s

After 2.5 seconds the final speed is

v_f = 15 m/s

so here we can use the formula of acceleration using kinematics

a = \frac{v_f - v_i}{t}

a = \frac{15 - 0}{2.5}

a = 6 m/s^2

so here it will accelerate at 6 m/s^2 rate.


#4

i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.

7 0
3 years ago
A 12.0-g bullet is fired horizontally into a 109-g wooden block that is initially at rest on a frictionless horizontal surface a
kykrilka [37]

Answer:

v₀ = 280.6 m / s

Explanation:

we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy,

We write the mechanical energy when the shock has passed the bodies

   Em₀ = K = ½ (m + M) v²

We write the mechanical energy when the spring is in maximum compression

Em_{f} = K_{e} \\= \frac{1}{2} kx^2\\    Em_0 = Em_{f}

½ (m + M) v² = ½ k x²

Let's calculate the system speed

   v = √ [k x² / (m + M)]

   v = √[152 ×0.78² / (0.012 +0.109) ]

   v = 27.65 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

   p₀ = m v₀

After the crash

p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

 p_0 =  p_{f}

  m v₀ = (m + M) v

  v₀ = v (m + M) / m

let's calculate

v₀ = 27.83 (0.012 +0.109) /0.012

  v₀ = 280.6 m / s

4 0
3 years ago
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