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4 years ago

What would the average speed in kph of a horse and rider be if they cover a total distance of 14 km in 249 minutes

Physics

1 answer:

romanna [79]4 years ago

8 0

Average speed = (distance covered) / (time to cover the distance)

Average speed = (14 km) / (249 min)

Average speed = (14/249) (km/min)

Average speed = (14/249) (km/min) x (60 min/hr)

Average speed = (14 x 60 / 249) km/hr

<em>Average speed = 3.37 km/hr</em>

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An electron and a proton, initially at rest, are pushed by the same force. Which of the two will have greater velocity?

yulyashka [42]

Answer:

B electron

Explanation:

electron will have greater velocity

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3 years ago

Identify the energy transformation that takes when place when you apply the brakes on a bicycle.

valina [46]

Um Kinetic, mechanical, potential idk

The rider is riding the nick so kinetic then mechanical making the bike move then potential stopping the bike

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3 years ago

22. What is the length of a pendulum that has a period of 0.500 s?

sergeinik [125]

6.21 cm

use the pendulum formula : $\sf \bold{\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}$

where

T is time or period
π is pie = 22/7
L is pendulum length
g is acceleration due to gravity

Given:

T = 0.500 s

g = 9.8 m/s²

solving step-wise:

$\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}$

$\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}$

$\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}$

$\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }$

$\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2$

$\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8$

$\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m$

1 m → 100 cm

$\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm$

$\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm$ { rounded to nearest hundredth }

6 0

2 years ago

Read 2 more answers

Two point charges of 60.0 C and -12.0 C are separated by a distance of 20.0 cm. A 7.00 C charge is placed midway between these t

iogann1982 [59]

Answer:

$4.5\times 10^{14} N$

Explanation:

$q_1=60 C$

$q_2=-12 C$

$q_3=7 C$

Distance between q1 and q2,d=20 cm

$r=\frac{d}{2}=\frac{20}{2}=10 cm=10\times 10^{-2} m$

1m =100 cm

Electric force on charge q3 due to charge q1

$F_1=\frac{kq_1q_3}{r^2}=\frac{9\times 10^9\times 60\times 7}{(10\times 10^{-2})^2}$ (away from q1)

Electric force on charge q3 due to charge q2

$F_2=\frac{kq_2q_3}{r^2}=\frac{9\times 10^9\times 12\times 7}{(10\times 10^{-2})^2}$ (attract toward q2)

Net force= $F=F_1+F_2$

$F=\frac{9\times 10^9\times 60\times 7}{(10\times 10^{-2})^2}+\frac{9\times 10^9\times 12\times 7}{(10\times 10^{-2})^2}$

$F=\frac{9\times 10^9\times 7}{(10\times 10^{-2})^2}(60+12)$

$F=4.5\times 10^{14} N$

5 0

4 years ago

Consider the surface with parametric equations .

balandron [24]

There are two ways to express the tangent plane equation. Given that it is the sum of the two distinct tangent vectors, its parametric equation is r=r0+sru+trv.

<h3>What does the parametric surface in calculus mean?</h3>

A surface in Euclidean space is considered to be parametric if it can be described by a parametric equation with two variables. Parametric representation is another reasonably general technique for describing a surface in addition to implicit representation.

On the other hand, tangent planes to a surface are planes that are "parallel" to the surface at the point where they barely touch it. Remember that this provides us with a point on the The tangent plane equation can be written in two different ways. The following point emerges from the surface and tangent plane meeting at (x0,y0):

learn more about Tangent planes refer

brainly.com/question/17748591

#SPJ4

5 0

1 year ago